WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Well structured WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy can serve as a valuable review tool before exams.

Classification of Diversity of Life: Taxonomy Class 9 WBBSE MCQ Questions

Multiple Choice Questions & Answers

Question 1.
The term ‘taxonomy’ was coined by-………………
A. John Ray
B. Linnaeus
C. Theophrastus
D. Augustin de Candolle
Answer:
D. Augustin de Candolle

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Question 2.
Who is known as the ‘father of zoology’?
A. Aristotle
B. Theophrastus
C. Hippocrates
D. John Ray
Answer:
A. Aristotle

Question 3.
Who is known as the ‘father of taxonomy’?
A. Aristotle
B. Theophrastus
C. Augustin de Candolle
D. Linnaeus
Answer:
D. Linnaeus

Question 4.
Systematics is-………………
A. Nomenclature
B. Identification
C. Classification
D. All of these
Answer:
A. Nomenclature

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Question 5.
The correct sequence of Linnaean hierarchy is-………………
A. Class-Phylum-Order-Family-Genus-Species
B. Phylum-Order-Class-Family-Genus-Species
C. Division-Class-Family-Order-Genus-Species
D. Division-Class-Order-Family-Genus-Species
Answer:
A. Class-Phylum-Order-Family-Genus-Species

Question 6.
‘Species’ was treated as a unit of classification by-………………
A. John Ray
B. Linnaeus
C. Huxley
D. Augustin de Candolle
Answer:
A. John Ray

Question 7.
Which of the following are categories of taxonomic hierarchy?
A. Family
B. Order
C. Genus
D. All of these
Answer:
D. All of these

Question 8.
Hierarchy in classification was proposed by-………………
A. Simpson
B. Linnaeus
C. Mayer
D. Hutchinson
Answer:
B. Linnaeus

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Question 9.
Which of the following is a taxonomic rank?
A. Mammalia
B. Animalia
C. Class
D. Plantae
Answer:
C. Class

Question 10.
Number of taxa in taxonomic hierarchy is-………………
A. 27
B. 7
C. 17
D. 9
Answer:
B. 7

Question 11.
Full form of ICBN is-………………
A. International Classification of Biological Nomenclature
B. International Code of Botanical Nomenclature
C. International Code of Biological Nomenclature
D. International Class of Biological Nomenclature
Answer:
B. International Code of Botanical Nomenclature

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Question 12.
The first and second word in a binomial nomenclature respectively indicates-………………
A. Genus and species
B. Species and genus
C. Family and genus
D. Family and species
Answer:
A. Genus and species

Question 13.
Scientific names of paddy plant and pea plant respectively are-………………
A. Pisum sativum and Oryza sativa
B. Oryza sativa and Plsum sativum
C. Triticum aestivum and Pisum sativum
D. Zea mays and Pisum sativum
Answer:
B. Oryza sativa and Plsum sativum

Question 14.
Which of the following covers highest number of organisms?
A. Species
B. Family
C. Class
D. Phylum
Answer:
D. Phylum

Question 15.
The scientific name of human should be correctly printed as-………………
A. Homo sapiens
B. Homosapiens sapiens
C. Homo Sapiens Sapiens
D. Homo sapiens sapiens
Answer:
D. Homo sapiens sapiens

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Question 16.
Which of the following is not in a correct hierarchical order?
A. Class-Order-Family
B. Family-Order-Class
C. Order-Family-Genus
D. Phylum-Class-Order
Answer:
B. Family-Order-Class

Question 17.
Binomial nomenclature is-………………
A. A scientific name comprising of a generic and a specific epithet
B. A Latin name
C. Scientific name given to a plant
D. One name given by two different scientists
Answer:
A. A scientific name comprising of a generic and a specific epithet

Question 18.
Binomial nomenclature was first published in the book-………………
A. Systema Naturae
B. Genera Plantarum
C. Species Plantarum
D. The Plants
Answer:
C. Species Plantarum

Question 19.
Scientific name of India’s national bird is-………………
A. Passer domesticus
B. Corvus splendens
C. Pavo cristatus
D. Columba livia
Answer:
C. Pavo cristatus

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Question 20.
Naturally interbreeding animals belong to the same-………………
A. Family
B. Class
C. Genus
D. Species
Answer:
D. Species

Question 21.
The author of the book ‘Systema Naturae’ is-…………………
A. Aristotle
B. John Ray
C. Linnaeus
D. Theophrastus
Answer:
C. Linnaeus

Fill in the blanks:

1. ……………. is known as the ‘father of botany’.
2. The smallest unit of classification is ……………
3. The concept of ‘binomial nomenclature’ was proposed by ……………..
4. A family comprises of related ……………..
5. The theoretical study of classification is known as ……………..
6. ICBN is the set of rules and recommendations used for naming ……………..
7. The highest rank of taxonomic hierarchy is called ……………..
Answer:
1. Theophrastus
3. Linnaeus
5. Taxonomy
7. Kingdom
2. Species
4. Genera
6. Plants

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

State True or False

1. Human beings belong to the kingdom Animalia. — True
2. The book ‘Species Plantarum’ was written by Augustin de Candolle. — False
3. Panthera tigris is the scientific name of India’s national animal. — True
4. Order is a category in Linnaean hierarchy. — True
5. Linnaean hierarchy consisted of 10 categories. — False
6. The category ‘division’ is used during the classification of plants. — True

Match the columns

Left column Right column
1. Peacock A. Panthera leo
2. Lion B. Pavo cristatus
3. Mango C. Pisum sativum
4. Pea D. Mangifera indica
E. Homo sapiens

Answer:
1-B; 2-A; 3-D; 4-C

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Left column Right column
1. Kingdom A. Dicotyledoneae
2. Division B. Mangifera
3. Class C. Angiospermae
4. Genus B. Sapindales
E. Piantae

Answer:
1-E; 2-C; 3-A; 4-B

Left column Right column
1. Cyanogen theory A. Lamarck
2. Systematics B. de Candolle
3. Taxonomy C. Pfluger
4. Biology B. Oparin
E. Linnaeus

Answer:
1-С; 2-Е; 3-B; 4-A

WBBSE Class 9 Life Science MCQ Questions Chapter 1.3A Classification of Diversity of Life: Taxonomy

Left column Right column
1, Concept of species A. Bentham and Hooker
2. Binomial nomenclature B. Ernst Mayr
3. Modern definition of species C. John Ray
4. Genera Plantarum D. Linnaeus
E. Darwin

Answer:
1-C; 2-D; 3-B; 4-A

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Well structured WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches can serve as a valuable review tool before exams.

Biology and its Branches Class 9 WBBSE MCQ Questions

Multiple Choice Questions & Answers

Question 1.
The branch of science that deals with the study of structures and life processes of living forms is called-………….
A. Psychology
B. Geology
C. Biology
D. Chemistry
Answer:
C. Biology

Question 2.
The Greek word ‘Bios’ means-………….
A. Life
B. Organism
C. Organic
D. Microbes
Answer:
A. Life

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Question 3.
Among the following, the oldest branch of biology is-………….
A. Cytology
B. Taxonomy
C. Histology
D. Ecology
Answer:
B. Taxonomy

Question 4.
Astrobiology or exobiology is a science which is developed by the combination of-………….
A. Biology and electronics
B. Biology and space science
C. Biology and astrology
D. Biology and computer science
Answer:
B. Biology and space science

Question 5.
The branch of biology that deals with the study of different types of tissues is -………….
A. Histology
B. Pathology
C. Ethology
D. Ecology
Answer:
A. Histology

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Question 6.
The branch of biology that deals with the study of interactions between living organisms and the environment is-………….
A. Pathology
B. Ethology
C. Ecology
D. Embryology
Answer:
C. Ecology

Question 7.
The branch of science that deals with the study of different diseases and their causes is-………….
A. Ethology
B. Anatomy
C. Pathology
D. Physiology
Answer:
C. Pathology

Question 8.
The study of structure and development of embryo, is known as-………….
A. Palaeontology
B. Ecology
C. Physiology
D. None of these
Answer:
D. None of these

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Question 9.
Physiology is the study of-………….
A. Different functional activities and life processes of an organism
B. Physical ability of an organism
C. Physical structure of an organism
D. Genes and its behaviour
Answer:
A. Different functional activities and life processes of an organism

Question 10.
Palaeontology is the study of-………….
A. Fossils
B. Embryos
C. Primitive plants
D. Primitive animals
Answer:
A. Fossils

Question 11.
The study of those animals, which cause harm to other organisms by drawing nutrients from them, is known as-………….
A. Cytology
B. Parasitology
C. Palaeontology
D. Entomology
Answer:
B. Parasitology

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Question 12.
The term ‘biology’ was coined by-………….
A. Lamarck
B. Oparin
C. Linnaeus
D. Huxley
Answer:
A. Lamarck

Question 13.
The branch of classical biology that deals with the study of different forms of life, their classification and naming, is known as-………….
A. Genetics
B. Cytology
C. Histology
D. Taxonomy
Answer:
D. Taxonomy

Question 14.
The branch of biology that deals with the study of plants, is called-………….
A. Zoology
B. Botany
C. Agriculture
D. Horticulture
Answer:
B. Botany

Question 15.
Zoology is the study of-………….
A. Zoos
B. Birds
C. Mammals
D. Animals
Answer:
D. Animals

Question 16.
Biometry is a branch of science, which is developed by the combination of biology, mathematics and-………….
A. Trigonometry
B. Geometry
C. Statistics
D. Electronics
Answer:
C. Statistics

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Question 17.
The branch of biology developed by the combination of biology and electronics is-………….
A. Bionics
B. Biometry
C. Cybernetics
D. Biophysics
Answer:
A. Bionics

Question 18.
The branch of biology that deals with the study of different aspects of cell, is known as-………….
A. Histology
B. Cytology
C. Physiology
D. Psychology
Answer:
B. Cytology

Question 19.
Study of humankind under the light of geography, sociology and palaeontology, is known as-………….
A. Geology
B. Anthropology
C. Human physiology
D. Human anatomy
Answer:
B. Anthropology

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Question 20.
Study of physiology of organisms in outer space, is known as-………….
A. Exobiology
B. Space science
C. Astronomy
D. Astrology
Answer:
A. Exobiology

Question 21.
Immunology is the branch of science that deals with-………….
A. Body’s own defence against infection
B. Action of hormone in the body
C. Action of medicines in the body
D. Action of toxins in the body
Answer:
A. Body’s own defence against infection

Question 22.
Oceanography is an inter-disciplinary science, that mainly deals with-…………..
A. Coastal geography and phycology
B. Marine science and robotics
C. Oceanic geology and marine biology
D. Aquatic biology and meteorology
Answer:
C. Oceanic geology and marine biology

Fill in the blanks:

1. Study of fungi is known as ………………
2. Ethology is the study of ……………… of organisms.
3. ………………deals with the study of crude drugs.
4. The scientific study of production of flowers and ornamental plants is known as……………….
5. The knowledge of is ……………. utilised to make different instruments like endoscope, microscope, etc.
6. Palaeontology is the science which is formed by the combination of biology and …………….
Answer:
1. Mycology
2. Behaviour
3. Pharmacognosy
4. Floriculture
5. Bionics
6. Geology

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

State True or False

1. Taxonomy is the oldest branch of biology. — True
2. Bio informatics is the branch of science which is a combination of biology and electronics. — False
3. Sericulture is a branch of applied biology. — True
4. Knowledge of microbiology is important for the production of antibiotics. — True
5. Knowledge of biology can be utilized to control population explotion. — True
6. Study of human behaviour is called thanatology. — False

Match the columns

Left column Right column
1. Apiculture A. Oysters
2. Pisciculture B. Honeybees
3. Sericulture C. Birds
4. Pearl culture D. Fishes
E. Silkworms

Answer:
1-B; 2-D; 3-E; 4-A

Left column Right column
1. Anthropology A. Study of genes
2. Cytology B. Study of humankind
3. Genetics C. Study of fossils
4. Palaeontology D. Study of cells
E. Study of embryo

Answer:
1-B; 2-D; 3-A; 4-C

WBBSE Class 9 Life Science MCQ Questions Chapter 1.2 Biology and its Branches

Left column Right column
1. Study of biomolecules A. Naked gene
2. Response to stimuli B. Microbiology
3. Study of microorganisms C. Mimosa pudica
3. Study of microorganisms C. Mimosa pudica

Answer:
1-E; 2-C; 3-B; 4-D

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Well structured WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use can serve as a valuable review tool before exams.

Natural Resources and its Sustainable Use Class 9 WBBSE MCQ Questions

Multiple Choice Questions :

Question 1.
The concept, which supports that conservation of environment and development of economy must go on parallely, is called-
(A) Human development
(B) Sustainable development
(C) Industrial development
(D) Unidirectional development
Answer:
(B) Sustainable development

Question 2.
A natural resource, which may be replenished is-
(A) Coal
(B) Forest
(C) Petroleum
(D) Natural gas
Answer:
(B) Forest

Question 3.
A non-renewabie natural resource is-
(A) Coal
(B) Solar energy
(C) Water
(D) Wood
Answer:
(A) Coal

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 4.
Trees of a forest continuously provide us-
(A) Furniture
(B) Oxygen
(C) Coal
(D) Wood
Answer:
(B) Oxygen

Question 5.
Most of the members of a forest are-
(A) Producers
(B) Decomposers
(C) Primary Consumers
(D) Secondary consumers
Answer:
(A) Producers

Question 6.
A forest cannot be used for-
(A) Pisciculture
(B) Apiculture
(C) Harvesting medicinal plants
(D) Ecotourism
Answer:
(A) Pisciculture

Question 7.
Which is not a cause of deforestation?
(A) Expansion of cultivation
(B) Forest fire
(C) Flood
(D) Industrial development
Answer:
(C) Flood

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 8.
Sudden deforestation in an area may be due to-
(A) Expansion of cultivation
(B) Industrial expansion
(C) Laying railway track
(D) Forest fire
Answer:
(D) Forest fire

Question 9.
Production of prawn is a practice of-
(A) Epiculture
(B) Horticulture
(C) Pisciculture
(D) Lac culture
Answer:
(C) Pisciculture

Question 10.
A conventional source of energy is-
(A) Sunlight
(B) Petroleum
(C) Wind
(D) All of these
Answer:
(B) Petroleum

Question 11.
A non-conventional source of energy is-
(A) Coal
(B) Natural gas
(C) Petroleum
(D) Wind
Answer:
(D) Wind

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 12.
Which of the following has a role in food production?
(A) Lac culture
(B) Agriculture
(C) Pearl culture
(D) None of these
Answer:
(A) Lac culture

Question 13.
Which part of forest trees prevents soil erosion?
(A) Shoot
(B) Root
(C) Root and shoot
(D) Stem
Answer:
(B) Root

Question 14.
Coal is used mostly in-
(A) Cooking
(B) Running rail engine
(C) Steel industry
(D) Thermal power plants
Answer:
(D) Thermal power plants

Question 15.
A renewable natural resource is-
(A) Livestock
(B) Natural gas
(C) Petroleum
(D) None of these
Answer:
(A) Livestock

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 16.
Deforestation causes-
(A) Soil erosion
(B) Global warming
(C) Drought
(D) All of these
Answer:
(D) All of these

Question 17.
The method of water conservation is-
(A) Plantation
(B) Rain water harvesting
(C) Digging water pits
(D) All of these
Answer:
(D) All of these

Question 18.
Source of Vitamin C and amino acid is-
(A) Sago
(B) Yam bean
(C) Moringa oleifera
(D) Gum arabic
Answer:
(C) Moringa oleifera

Question 19.
Which appliance does help in conservation of energy?
(A) Refrigerator
(B) Solar water heater
(C) Computer
(D) Air purifier
Answer:
(B) Solar water heater

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 20.
One of the non-human causes of deforestation is-
(A) Expansion of grazing land
(B) Expansion of cultivating land
(C) Industrial expansion
(D) Forest fire
Answer:
(D) Forest fire

Question 21.
Main problem for Indian rivers is-
(A) Water scarcity
(B) Silting
(C) Low water current
(D) Pollution
Answer:
(D) Pollution

Question 22.
The World summit on ‘Fight against hunger’, organised by United Nation’s Food and Agriculture Organisation was held in Rome in-
(A) 1996
(B) 1999
(C) 2003
(D) 2006
Answer:
(A) 1996

Question 23.
Pisciculture deals with-
(A) Culture of mushroom
(B) Culture of poultry birds
(C) Culture of prawn
(D) Culture of fish
Answer:
(D) Culture of fish

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 24.
Source of fruits and vegetables is-
(A) Horticulture
(B) Floriculture
(C) Apiculture
(D) Pisciculture
Answer:
(A) Horticulture

Question 25.
Most modern concept of environmental development is-
(A) Urbanization
(B) Sustainable development
(C) Control of industrialisation
(D) Deforestation
Answer:
(B) Sustainable development

Question 26.
Social development, economical development and ecological development are the three basic steps of-
(A) Human development
(B) Industrial development
(C) Sustainable development
(D) Unidirectional development
Answer:
(C) Sustainable development

Question 27.
Most of the forests in India are of type.
(A) Deciduous
(B) Evergreen
(C) Coniferous
(D) Mangrove
Answer:
(A) Deciduous

Question 28.
The type of forest, which has most economic utility is-
(A) Deciduous
(B) Evergreen
(C) Coniferous
(D) Mangrove
Answer:
(C) Coniferous

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 29.
Which of the following does not occur due to forestation?
(A) Water cycle regulation
(B) Acid rain
(C) Flood control
(D) Climate regulation
Answer:
(B) Acid rain

Question 30.
Which of the following is a cause of deforestation?
(A) Excess agriculture
(B) Excess industry
(C) Urbanisation
(D) All of these
Answer:
(D) All of these

Question 31.
Which of the following should be done before cutting a tree?
(A) At least three similar trees should be planted
(B) Appoint skilled workers for cutting trees
(C) Marking other trees to be cut
(D) Plan to sell those cut trees
Answer:
(A) At least three similar trees should be planted

Question 32.
Which of the following is not a function of forest?
(A) Maintaining O2 – CO2 balance
(B) Reduction of soil erosion
(C) Reduction of rainfall
(D) Food and wood production
Answer:
(C) Reduction of rainfall

Question 33.
The combined mass of water found in all water bodies on earth, is called-
(A) Atmosphere
(B) Hydrosphere
(C) Lithosphere
(D) Biosphere
Answer:
(B) Hydrosphere

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 34.
Which of the following should not be present in drinking water?
(A) Magnesium
(B) Soluble CO2
(C) Sodium salt
(D) Harmful bacteria
Answer:
(D) Harmful bacteria

Question 35.
Which of the following step should be taken for reducing wastage of water?
(A) Store water at the earliest
(B) Stop unnecessary use of water
(C) Prevent water pollution
(D) All of these
Answer:
(D) All of these

Question 36.
Rain water is not always safe for household purpose because of-
(A) Absence of mineral salts
(B) Presence of organic acid
(C) Presence of few protozoa
(D) Presence of inorganic acid
Answer:
(D) Presence of inorganic acid

Question 37.
Use of which of the following reduces use of fossil fuels?
(A) Solar car
(B) Microwave oven
(C) Biofuels
(D) All of these
Answer:
(D) All of these

Question 38.
Pearl culture is a type of-
(A) Tissue culture
(B) Apiculture
(C) Horticulture
(D) Mariculture
Answer:
(D) Mariculture

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 39.
Growing and cultivation of trees is termed as –
(A) Silviculture
(B) Horticulture
(C) Tissue culture
(D) Floriculture
Answer:
(A) Silviculture

Question 40.
Example of an alternative food source is-
(A) Rice
(B) Pulse
(C) Meat
(D) Single cell protein
Answer:
(D) Single cell protein

Question 41.
Which of the following is not associated with food production?
(A) Horticulture
(B) Agriculture
(C) Pisciculture
(D) Pearl culture
Answer:
(D) Pearl culture

Question 42.
An example of fossil fuel is-
(A) Wood
(B) Coal
(C) Uranium
(D) Both (A) (B)
Answer:
(B) Coal

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 43.
In which of the following countries, utilization of energy is not increasing any more?
(A) America
(B) India
(C) Bangladesh
(D) China
Answer:
(A) America

Question 44.
Which of the following is a cause of food crisis?
(A) Change in climate
(B) Natural calamities
(C) Population explosion
(D) All of these
Answer:
(D) All of these

Fill in the blanks :

  1. The litter on the forest floor, is partly decomposed to form sticky _____.
  2. _____ is used to prepare chewing gum.
  3. _____ is the main economically important product of forest.
  4. Rain water has a slightly _____ pH.
  5. Sago is extracted from _____ trees.
  6. Coal, petroleum, natural gas are the conventional sources for _____ power.
  7. _____ by trees increases humidity of air.
  8. _____ is the conventional source for hydel power.

Answer:

  1. Humus
  2. Gum arabic
  3. Timber
  4. Acidic
  5. Palm
  6. Thermal
  7. Transpiration
  8. Water

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

State true or false :

  1. Ecotourism is a productive aspect of forest, from which government earns huge amount of money.
  2. Due to deforestation, concentration of greenhouse gases increases in the atmosphere.
  3. Fossil fuels are renewable sources of energy.
  4. Rain water is generally free from germs and contaminants.
  5. Sago is a protein-rich matter.
  6. Rain water harvesting is practiced in areas with excessive suspended particulate matters in air.
  7. Afforestation helps to reduce soil erosion.
  8. Fossil fuels include coal and natural gas only.
  9. Coal, natural gas, firewood are examples of non-conventional energy sources.
  10. Forestation along the slope of watershed reduces the deposition silt in riverbed.

Answer:

  1. True
  2. True
  3. False
  4. True
  5. False
  6. False
  7. True
  8. False
  9. False
  10. True

Match the columns :

Question 1.

Left column Right column
1. Local use of forest A. Flood and drought
2. Cause of deforestation B. Ecotourism
3. Result of deforestation C. Honey, timber
4. Productive use of forest D. Rain water harvesting
E. Urbanisation

Answer:

Left column Right column
1. Local use of forest C. Honey, timber
2. Cause of deforestation E. Urbanisation
3. Result of deforestation A. Flood and drought
4. Productive use of forest B. Ecotourism

WBBSE Class 9 Life Science MCQ Questions Chapter 5.2 Natural Resources and its Sustainable Use

Question 2.

Left column Right column
1. Non conventional energy sourc A. Vegetables, spices
2. Poultry B. Yam bean, sago
3. Horticulture C. Eggs, meat
4. Alternative food source D. Coal, kerosene oil
E. Geothermal energy

Answer:

Left column Right column
1. Non conventional energy sourc E. Geothermal energy
2. Poultry C. Eggs, meat
3. Horticulture A. Vegetables, spices
4. Alternative food source B. Yam bean, sago

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Well structured WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life can serve as a valuable review tool before exams.

Basic Properties of Life Class 9 WBBSE MCQ Questions

Multiple Choice Questions & Answers

Question 1.
One of the basic properties of a living organism is- …………………….
A. To intake oxygen
B. To move
C. To reproduce
D. To absorb water
Answer:
A. To intake oxygen

Question 2.
All reactions of life take place within the- …………………….
A. Nucleus
B. Mitochondrion
C. Chromosome
D. Protoplasm
Answer:
D. Protoplasm

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 3.
All the biochemical processes occurring within a living organism in order to sustain life, are collectively known as- …………………….
A. Energy
B. Metabolism
C. Nutrition
D. Digestion
Answer:
B. Metabolism

Question 4.
The concept of spontaneous generation of life was first proposed by- …………………….
A. Haldane and Oparin
B. Aristotle
C. Urey and Miller
D. Melvin Calvin
Answer:
B. Aristotle

Question 5.
The concept of origin of life from inorganic matter is known as-…………………….
A. Special creation
B. Chemosynthesis
C. Biogenetic concept
D. Pangenesis
Answer:
B. Chemosynthesis

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 6.
The first step of chemical origin of life was the-…………………….
A. Origin of coacervates
B. Origin of complex organic compounds
C. Origin of simple organic compounds
D. Origin of proteinoids
Answer:
C. Origin of simple organic compounds

Question 7.
The essential gaseous ingredient of present atmosphere, which was absent in the primitive atmosphere before the origin of life, is-…………………….
A. Carbon dioxide
B. Nitrogen
C. Oxygen
D. Carbon monoxide
Answer:
C. Oxygen

Question 8.
The concept of chemosynthesis of life on earth was proposed by-…………………….
A. Aristotie
B. Miller and Urey
C. Oparin and Haldane
D. Sidney Fox
Answer:
C. Oparin and Haldane

Question 9.
According to Cosmozoic theory or Panspermia, the reason of origin of life is-…………………….
A. Extraterrestrial objects, such as comet
B. Biochemical reactions
C. Spontaneous creation
D. None of these
Answer:
A. Extraterrestrial objects, such as comet

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 10.
The simple compound present in the primitive earth, was-…………………….
A. H2O
B. NH3
C. CH4
D. All of these
Answer:
D. All of these

Question 11.
The simple organic matter produced from the inorganic compounds during chemosynthesis of life was-…….
A. Fatty acids
B. Amino acids
C. Both A& B.
D. None of these
Answer:
C. Both A& B.

Question 12.
Coacervate, as proposed by Oparin, was mainly composed of-…………………….
A. Lipids
B. Proteins
C. Carbohydrates
D. All of these
Answer:
A. Lipids

Question 13.
‘Hot dilute soup’ produced in the primitive ocean contained-…………………….
A. Amino acids and fatty acids
B. Purines and pyrimidines
C. Simple sugars
D. All of these
Answer:
D. All of these

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 14.
Formation of proteinoids, before the origin of primordial cell, was explained by-…………………….
A. A I Oparin
B. J B S Haldane
C. Stanley Miller
D. Sidney Fox
Answer:
D. Sidney Fox

Question 15.
The term ‘biodiversity’ was coined by-…………………….
A. Norman Myers
B. Alexander Oparin
C. Gaylord Nelson
D. W G Rosen
Answer:
D. W G Rosen

Question 16.
In the laboratory experiment of chemosynthesis of organic matters from simple inorganic compounds, Urey and Miller used-…………………….
A. NH3 ,CH4 ,H2O
B. H2O, NH3,CH4, H2
C. NH3, CH4, H2O, O2
D. All of these
Answer:
B. H2O, NH3,CH4, H2

Question 17.
The energy required for the chemical reactions, which occur during chemosynthesis of life, was obtained from-…………………….
A. Extreme heat of the primitive earth
B. Cosmic rays
C. Lightning
D. All of these
Answer:
D. All of these

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 18.
In primitive ocean, proteinoids were formed by polymerisation of-…………………….
A. Sugar molecules
B. Fatty acids
C. Nucleic acids
D. Protein molecules
Answer:
D. Protein molecules

Question 19.
The basic physical component of life is-…………………….
A. Nucleic acid
B. Glycerol
C. Glucose
D. Nucleoside
Answer:
A. Nucleic acid

Question 20.
Protobionts are-…………………….
A. A cluster of microsphere molecules, surrounded by a membrane
B. A cluster of protein molecules, surrounded by a lipid layer
C. A cluster of proteinoids, covered with a limiting membrane
D. Nothing but protocells
Answer:
D. Nothing but protocells

Question 21.
The first phase of chemical reactions during chemosynthesis of organic matters started in-…………………….
A. Atmosphere
B. Primitive ocean
C. Earth’s surface
D. Beneath earth’s crust
Answer:
A. Atmosphere

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 22.
During origin of life, the atmosphere of earth was-…………………….
A. Oxidising
B. Reducing
C. Partially oxidised and partially reduced
D. None of these
Answer:
B. Reducing

Question 23.
The ‘Cyanogen hypothesis’ was given by-…………………….
A. Pfluger
B. Daniken
C. Miller
D. Arrhenius
Answer:
A. Pfluger

Question 24.
Origin of life on the earth was manifested by the formation of-…………………….
A. Microspheres
B. Proteinoids
C. Nucleic acids
D. Protobionts
Answer:
D. Protobionts

Question 25.
Life on the earth originated about-…………………….
A. 2.5 billion years back
B. 4.4 billion years back
C. 3.7 million years back
D. 4.5 million years back
Answer:
B. 4.4 billion years back

Question 26.
The main role played by the organisms in transforming the de-oxidised atmosphere of the primitive earth into an oxidising one, are-…………………….
A. Green plants
B. Photosynthetic bacteria
C. Algae
D. Cyanobacteria
Answer:
D. Cyanobacteria

Question 27.
According to Sidney Fox, prior to the origin of life, numerous thin membrane-bound proteinoid-clusters were termed as-…………………….
A. Coacervates
B. Microspheres
C. Protocells
D. Protobionts
Answer:
B. Microspheres

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 28.
The relentless effort of a living organism to adjust itself with the changing environment, is called-…………………….
A. Adaptation
B. Migration
C. Evolution
D. Natural selection
Answer:
A. Adaptation

Question 29.
Mutation in organisms occurs-…………………….
A. Slow and steadily
B. With the change in nature
C. Suddenly and temporarily
D. Suddenly and permanently
Answer:
D. Suddenly and permanently

Question 30.
The assumed temperature of the earth during its origin was about-…………………….
A. 2000°-3000°C
B. 3000°-4000°C
C. 400°-500°C
D. 5000°-6000°C
Answer:
D. 5000°-6000°C

Question 31.
The ‘Ancient Astronauts’ hypothesis of origin of life was proposed by scientist-…………………….
A. Pfluger
B. Pasteur
C. Urey
D. Daniken
Answer:
D. Daniken

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Question 32.
The physical basis of life is-…………………….
A. Cell
B. Endoplasm
C. Protoplasm
D. Cytoplasm
Answer:
C. Protoplasm

Question 33.
‘Naked gene’ is not covered by-…………………….
A. Plasma membrane
B. Lipid membrane
C. Peptidoglycan membrane
D. Nuclear membrane
Answer:
D. Nuclear membrane

Fill in the blanks:

1. The first nucleic acid which originated on earth was …………….
Answer: RNA

2. The country with the richest biodiversity on earth, is …………….
Answer: Brazil

3. Eye colour is an example of ……………. variation.
Answer: Discontinuous

4. The earliest photosynthetic living organism on this earth was …………….
Answer: Cyanobacteria

5. The concept of spontaneous generation of life was rejected by …………….
Answer: Pasteur

6. ……………. and nucleic acid combined together to form life on primitive earth.
Answer: Protein

7. ……………. is responsible for discontinuous variation.
Answer: Mutation

8. Proteinoid molecules conjugate to form …………….
Answer: Microspheres

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

State True or False

1. Adaptability is the ability of a living organism to adjust with the changing environment. — True
2. Biogenesis is a synonym of biopoiesis. — False
3. Scientist Haldane coined the term ‘primordial soup’. — False
4. Hydrogen was the predominant gas in the primitive atmosphere. — True
5. Mimosa pudica respond to stimulus. — True
6. Alpha diversity is called turnover diversity. — False

Match the columns

Left column Right column
1. Biochemical theory of life A. Aristotle
2. Microsphere B. Oparin
3. Spontaneous generation C. Haldane
4. Hot dilute soup D. Stanley Miller
E. Sidney fox

Answer:
1-B; 2-E; 3-A; 4-C

WBBSE Class 9 Life Science MCQ Questions Chapter 1.1 Basic Properties of Life

Left column Right column
1. Human weight A. Beta diversity
2. Species richness in an area B. Discontinuous variation
3. Turnover diversity C. Gamma diversity
4. Human eye colour D. Alpha diversity
E. Continuous variation

Answer:
1-E; 2-D; 3-A; 4-B

 

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Detailed explanations in West Bengal Board Class 9 Life Science Book Solutions Chapter 3.2A Respiration: Organ-Level Respiration offer valuable context and analysis.

WBBSE Class 9 Science Chapter 3.2A Question Answer – Respiration: Organ-Level Respiration

Very Short Questions and Answers : (1 mark for each question)

Question 1.
Which physiological process provides energy to perform life activities?
Answer:
Respiration provides energy to perform life activities.

Question 2.
Which typical respiratory organ is seen in halophytic plants?
Answer:
Pneumatophore or breathing root is the typical respiratory organ of the halophytic plants.

Question 3.
Name two organisms, which exchange respiratory gases through body surface.
Answer:
Amoeba and Hydra exchange respiratory gases through body surface.

Question 4.
Name two invertebrates, which perform organ-level respiration by skin.
Answer:
Earthworms and leeches are two invertebrates which perform organ-level respiration by skin.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 5.
Name two invertebrates, which perform organ-level respiration by gills.
Answer:
Crabs and prawns perform organ-level respiration by gills.

Question 6.
Name a vertebrate, which is capable of performing organ-level respiration by skin.
Answer:
Frogs are capable of performing organ-level respiration through skin.

Question 7.
Which parts of gills act as the site of gaseous exchange?
Answer:
Gill lamellae act as the site of gaseous exchange.

Question 8.
Which part of lungs act as the site of gaseous exchange?
Answer:
Alveoli of lungs act as the site of gaseous exchange.

Question 9.
Mention a common feature of gill lamellae and alveoli of lungs.
Answer:
Both gill lamellae and alveoli of lungs are well vascularised.

Question 10.
Name two parts of the human respiratory system, which do not take part in gaseous exchange?
Answer:
Trachea and bronchioles do not take part in gaseous exchange.

Question 11.
Through which opening, air enters into the trachea from pharynx?
Answer:
Air enters into the trachea from pharynx through an opening, called glottis.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 12.
Where is larynx located?
Answer:
Larynx is located at the upper end of the trachea.

Question 13.
Where is bronchus located?
Answer:
Bronchus is located at the lower end of the trachea.

Question 14.
Which bony structure holds the gill lamellae in fishes?
Answer:
In fishes, the gill lamellae are held by bony gill arch.

Question 15.
Which bony plate covers the gill chamber of bony fishes?
Answer:
Operculum covers the gill chamber of bony fishes.

Question 16.
Which fine tubular structures supply air directly to the cells in the body of insects?
Answer:
Tracheoles supply air directly to the cells in the body of insects.

Question 17.
How much air does a healthy adult human inhale or exhale during normal breathing?
Answer:
A healthy adult human inhales or exhales 500 ml of air during normal breathing.

Question 18.
What is the maximum volume of air, which a healthy adult human can hold in the lungs?
Answer:
A healthy adult human can hold a maximum of 4500-5000 \mathrm{ml} of air in the lungs.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 19.
How can a person increase the vital capacity of the lungs?
Answer:
A person can increase the vital capacity of the lungs by performing breathing exercises or ‘pranayam’.

Question 20.
Mention two very common diseases caused due to smoking.
Answer:
Smoking causes emphysema and COPD (Chronic Obstructive Pulmonary Disease).

Question 21.
Name the flattened sheet of respiratory muscle, which separates the thoracic cavity from the abdominal cavity.
Answer:
The flattened sheet of respiratory muscle which separates the thoracic cavity from abdominal cavity, is called diaphragm.

Question 22.
Which typical structure prevents the entry of food particles into the larynx?
Answer:
A cartilaginous valve, called epiglottis, prevents entry of food particles into the larynx.

Question 23.
Which structures prevent flattening of trachea during exhalation?
Answer:
There are 16 to 20 half ring-like cartilaginous structures, fitted anteriorly to the trachea, which prevent its flattening during exhalation.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 24.
What is the accessory respiratory organ of Koi fish called?
Answer:
The accessory respiratory organ of Koi fish is called labyrinth organ.

Question 25.
Name two muscles of human body, which help in breathing.
Answer:
Intercostal muscles and muscular diaphragm of human body help in breathing.

Question 26.
Name the two parts of pleura.
Answer:
The outer part of pleura is called parietal pleura, and the inner part of pleura is called visceral pleura.

Question 27.
Name a respiratory pigment of vertebrates.
Answer:
A respiratory pigment of vertebrates is haemoglobin.

Question 28.
Name a respiratory pigment of invertebrates.
Answer:
A respiratory pigment of invertebrates is haemocyanin.

Question 29.
When do frogs respire through their skin?
Answer:
Frogs respire through their skin during hibernation (i.e. winter sleep).

Short Questions and Answers : (2 marks for each question)

Question 1.
What is meant by organ-level respiration?
Answer:
The physical process involving the intake of oxygen in the body and release of carbon dioxide from the body, with the help of typical respiratory organs, is known as organ-level respiration.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 2.
How do unicellular organisms perform organlevel respiration?
Answer:
Unicellular organisms do not possess organs, therefore they do not perform organ-level respiration, but perform gaseous exchange of O2 and CO2 by diffusion through cell membrane.

Question 3.
How do sponges and jellyfishes perform organ-level respiration without respiratory organ?
Sponges and jellyfishes do not have any respiratory organ. Their body cells perform gaseous exchange by diffusion through respective cell membranes. This is how they perform organlevel respiration.

Question 4.
How does the skin of earthworm act as a respiratory organ?
Answer:
The skin of earthworm always remain moist. Atmospheric oxygen is dissolved in the film of fluid over the skin surface. By diffusion, this gas gets mixed in the blood of the capillaries below the skin. Blood plasma of earthworm contains haemoglobin, which receives oxygen and carries it to different parts of the body. This is how the skin of earthworm acts as a respiratory organ.

Question 5.
Mention the role of spiracles and trachea in the respiration of cockroaches.
Answer:
In cockroaches, 10 pairs of spiracles are present at the two lateral sides of the body. Through these pores air enters into the trachea. Trachea forms an intricate network inside the body of cockroach, which ramifies into several branches that help in gaseous exchange.

Question 6.
When and how toads and frogs perform organ-level respiration by skin?
Answer:
Frogs and toads perform organ-level respiration by skin during hibernation. They have moist, naked glandular skin. This is well permeable to gases. The cutaneous capillaries below the skin can absorb oxygen from atmosphere by diffusion, which may fulfill their need of oxygen during hibernation.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 1

Question 7.
How does smoking affect lungs?
Answer:
Smoke of cigarettes and bidis contains different harmful compounds. This smoke enters the human lungs and forms a sticky tar which accumulates in the walls of the alveoli. Due to continuous smoking gradually the lungs lose the ability of gaseous exchange. The harmful compounds cause several diseases like emphysema, COPD and even lung cancer.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 8.
How many types intercostal muscles are there? Name them.
Answer:
There are two types of intercostal musclesexternal intercostal muscles and internal intercostal muscles. These muscles are present in between 12 pairs of rib bones.

Question 9.
Distinguish between trachea of cockroach and trachea of human.
Answer:

Features Trachea of cockroach Trachea of human
1. Number and shape Many, which form a network Single and straight
2. Larynx Absent Present
3. Opening Opens through many paired spiracles Opens through glottis
4. Termination Terminates as fine blind tubules within tissues Terminates into numerous tiny balloon-shaped alveoli

Long Questions and Answers : (5 marks for each question)

Question 1.
What is inhalation and exhalation? Briefly describe the salient features of the respiratory organs of animals. 2 + 3
Answer:
Inhalation
The mechanical process, by which organisms take in air from the environment, is called inhalation.

Exhalation
The mechanical process, by which living organisms give out carbon dioxide-rich air from their respiratory organs, into the environment, is called exhalation.

Salient features of the respiratory organs of animals
Respiratory organs of animals have three main distinctive features, which are mentioned below.
1. Moistness: A typical respiratory organ should be moist, which helps it to trap oxygen before diffusion. Moist cell membrane of unicellular organisms and moist skin of earthworms, leeches, frogs and toads trap atmospheric oxygen very efficiently.

2. Surface area: A respiratory organ should have a large surface area because more surface area improves its efficiency by transporting or exchanging enough oxygen. The thin and numerous lamellae of gills and densely packed alveoli of lungs make these two organs best suited for aquatic & aerial respiration respectively.

3. Vascularity: A respiratory organ should be well vascularised. This helps in better exchange of the respiratory gases. Rich distribution of blood capillaries in gills and lungs make these respiratory organs highly efficient for gaseous exchange.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 2.
Explain the role of different parts of plant body in gaseous exchange.
Answer:
Role of different parts of plant body in gaseous exchange
Plants do not have typical respiratory organs like animals. Few sites on a plant body help in exchange of O2 and CO2. These are stomata, lenticels, pneumatophores etc. Their role in gaseous exchange is mentioned below.

1. Stomata: Stomata are the tiny pores, present on the surface of leaves, tender stems and other parts of the plant body that help in the exchange of gases. These are the special intracellular spaces bordered by two specialised bean-shaped parenchyma cells, called guard cells, which open and close. Thus, allowing exchange of gases.

2. Lenticels: Lenticels are lens-shaped spaces, formed in the cracks on the bark of trees. These function as pores, providing the pathway for direct exchange of gases between the internal tissues and atmosphere through the bark, which is otherwise impermeable to gases.

3. Pneumatophores: Halophytes (mainly mangrove trees) grow on saline muddy soil in the delta region of rivers. This soil has poor oxygen content. To counter it, some roots of these plants grow vertically upward against gravity and come above the soil. These roots are highly porous. These are called pneumatophores or breathing roots, which help in the exchange of gases directly from the air.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 2

Question 3.
How do insects perform organ-level respiration with the help of trachea?
Answer:
Tracheal respiration in insects
In insects (such as cockroach), a network of a very thin-walled tubes are spread in the body. These tubes are known as trachea. Air enters into the tracheal system through tiny paired pores present on pleurites along the two sides of the body. These pores are called spiracles.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 3

Trachea ramifies or form branches inside the body cavity, longitudinally and transversely to form a tracheal network. The finest ends of tracheal branches are called tracheoles. Each tracheole ends in a large tracheal end cell, which gives off some fine cytoplasmic processes. These processes enter into intercellular tissue fluid. Gaseous exchange occurs between the tracheal end cells and tissue fluid and finally from tissue fluid to the cells by the process of diffusion.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 4.
Briefly describe the main respiratory organ of fishes. How do fishes perform aquatic respiration? 3 + 2
Answer:
Structure of respiratory organ of fishes
Gills perform the respiratory function in fishes. In case of cartilaginous fishes, these are present in gill clefts and in bony fishes, these are held in gill chambers at two sides of the head, covered with a bony plate, called the operculum. A gill has a curved bony skeletal structure, called gill arch. Two rows of thin and flat gill filaments are densely arranged in a parallel manner along the gill arch like teeth of a comb. Numerous, very thin membranous folds emerge from either side of a gill filament, called gill lamellae. Gill filaments and lamellae are supplied with dense network of blood capillaries.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 4

Mechanism of aquatic respiration in fishes
Fishes continuously open and close their mouth. When they open their mouth, fresh water flows into the buccal cavity. They open the opercula to allow water to pass through gills to flood the gill filaments before leaving the two gill chambers. As the water passes through the gills, O2 diffuses into the blood capillaries and CO2 diffuses out in the water. This is how, fishes perform aquatic respiration.

Question 5.
Describe the structure of human lung.
Answer:
Structure of human lung
WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 5

Lungs are paired, sac-like structures located in the thoracic cavity of human body, well protected by the rib cage. Lungs remain separated from the abdominal cavity by a muscular sheet or membrane, called the diaphragm. Each lung is covered with a double layered covering called pleura. The outer layer is called parietal and the inner one is called visceral pleura. A fluid-filled space is present in between these two layers. The left lung is slightly smaller with two lobes to accommodate the heart and the right one is larger with three lobes.

A long, thin walled, tubular wind-pipe or trachea goes down vertically along the medial chest line and divides into two bronchi (singular-bronchus) before entering the lungs. Each bronchus then ramifies several times, from finer to finest air tubules, called bronchioles. Finally, each of the bronchioles ends into a tiny balloon shaped alveolus (plural-alveoli). Thus, countless alveoli form a lung. Two human lungs are composed of 30 to 50 crore of alveoli. Wall of each alveolus is rich in blood capillaries. That is why healthy lungs appear reddish pink.

Question 6.
Describe the breathing mechanism of man.
Answer:
Mechanism of human breathing
The organ-level respiration or breathing in man involves two phases-
1. Inspiration
2. Expiration. The mechanism of breathing is discussed below.

1. Inspiration: The events which occur during inspiration are as follows-

As we breathe in, diaphragm muscles contract and move down towards the abdominal cavity.
Intercostal (present in between ribs) muscles contract to pull the ribs upward to some extent.
By these two actions, the space inside the ribcage increases. This reduces the pressure inside the chest cavity and in the pleural fluid.

In this situation, thoracic pressure reaches below the atmospheric pressure. As a result, oxygen-rich air from the atmosphere rushes into the body through nostrils, nasal passage, glottis, larynx, trachea, bronchus and bronchioles to reach the alveoli. Gaseous exchange occurs in between alveolar air and capillary blood. After this exchange, the air inside lungs become rich in carbon-dioxide (CO2). After this, the brain sends signal for expiration.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 6

2. Expiration: The events which occur during expiration are as follows-

  • The diaphragm expands and moves towards the chest cavity.
  • Intercostal muscles relax and the ribs go downward to their normal position.
  • Due to the above two actions, the internal volume of the chest cavity reduces. As a result, pressure increases in the pleural fluid, as well as in the lungs.
  • The lungs contract and the CO2-rich air, inside the lung, is pushed out along the reverse path.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration: Organ-Level Respiration

Question 7.
How do the lungs get weak and diseased? How can the lungs be kept fit? 3 + 2
Answer:
Reason of weak and diseased lungs
Lungs are very important organs in our body, which are involved in respiration. If lungs do not perform their function perfectly, we will fall sick. Lungs lose its efficienc due to aging, obesity, infections and in most cases due to smoking. A dark coloured tar is deposited in the lungs of smokers, that contains several potential carcinogens (cancer inducing substances), leading to lung cancer.

Smokers develop a chronic lung disease, called emphysema. In this case, gaseous exchange reduces and the efficiency of lungs decline permanently. Passive smokers (who unconsciously inhale the smoke released by active smokers) are the worst victims of this bad habit and also suffer from the same diseases. Due to allergic effect, a person may suffer from asthma and COPD (Chronic Obstructive Pulmonary Disease). Infection with Mycobacterium tuberculosis may lead to a serious lung disease, called tuberculosis, whose symptoms are coughing (sometimes with sputum with blood), chest pain, weakness, weight loss, fever etc.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 7

Methods of keeping the lungs fit
Breathing exercise or ‘pranayam’ keeps our lungs healthy. The basis of this exercise is steady, forceful & rhythmic inspiration & expiration. It increases the extensibility of the lungs and thus, increases the oxygen intake capacity of the body. But, pranayam should be practiced under the proper guidance of a competent yoga teacher. Moreover, swimming, cycling, jogging and even walking keeps our lungs healthy.

WBBSE Class 9 Life Science Solutions Chapter 3.2A Respiration Organ-Level Respiration 8

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Detailed explanations in West Bengal Board Class 9 Life Science Book Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases offer valuable context and analysis.

WBBSE Class 9 Science Chapter 3.1D Question Answer – Movement of Water, Minerals, Food and Gases

Very Short Questions and Answers : (1 mark for each question)

Question 1.
By which process water molecules enter through the cell membrane of root hair cells?
Answer:
Water molecules enter through the cell membrane of root hair cells by endosmosis.

Question 2.
How do cells of aquatic plants absorb dissolved CO2 from water?
Answer:
Aquatic plants absorb dissolved CO2 from the water by diffusion.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 3.
How is facilitated diffusion different from active transport?
Answer:
In active transport, chemical energy is needed in the form of ATP but facilitated diffusion does not need energy.

Question 4.
In which type of active transport, two different diffusible molecules or ions move against each other at the same time?
Answer:
In antiport, two different diffusible molecules or ions move against each other at the same time.

Question 5.
In which type of active transport, a single type of ion or molecule moves through the cell membrane?
Answer:
In uniport, a single type of ion or molecule moves through the cell membrane.

Question 6.
In which type of active transport, two different ions or molecules move together in the same direction through a cell membrane?
Answer:
In symport, two different ions or molecules move together in the same direction through a cell membrane.

Question 7.
Name two biomolecules, which pass through the cell membrane by active transport.
Answer:
Glucose and amino acids pass through the cell membrane by active transport.

Question 8.
Mention two matters, which are taken into a cell by passive transport.
Answer:
Oxygen and water are two matters, which are taken into a cell by passive transport.

Question 9.
Diffusion pressure deficit increases in leaves during daytime due to which phenomenon?
Answer:
Diffusion pressure deficit increases in leaves during the daytime due to transpiration.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 10.
How does sap pass through the cells of cortex of root?
Answer:
Sap passes through the cells of cortex of root by cell to cell osmosis.

Question 11.
Which pressure is created within the xylem vessels by the inflow of sap from the root?
Answer:
Root pressure is created within the xylem vessels by the inflow of sap from the root.

Question 12.
Which force pulls the sap up from roots to the leaves of tall plants?
Answer:
Transpiration pull helps the sap to reach the top leaves of tall plants.

Question 13.
How much pulling force may transpiration pull create in a xylem vessel?
Answer:
About 20 atmospheric pressure is created in the xylem vessels of taller plants by transpiration pull.

Question 14.
How does the size of diffusible molecules affect the rate of diffusion?
Answer:
Larger size of diffusible molecules reduces the rate of diffusion and vice versa.

Question 15.
How does the density of diffusible molecules affect the rate of diffusion?
Answer:
Higher density of diffusible molecules increases the rate of diffusion.

Question 16.
Due to which pressure young meristematic cells grow in size?
Answer:
Young meristematic cells grow in size due to turgor pressure.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 17.
Name the scientist who proposed the ‘Root Pressure Theory’.
Answer:
British scientist Stephen Hales proposed the ‘Root Pressure Theory’.

Question 18.
Who proposed the ‘Transpiration pull and Cohesion Tension Theory’ to explain the ascent of sap?
Answer:
Scientists Dixon and Joly proposed the ‘Transpiration pull and Cohesion tension theory’ to explain the ascent of sap.

Question 19.
Give an example of an impermeable membrane.
Answer:
An example of an impermeable membrane is plastic sheet.

Question 20.
Give an example of a permeable membrane.
Answer:
Cell wall is an example of a permeable membrane.

Question 21.
Give an example of a semi-permeable membrane.
Answer:
An example of a semi-permeable membrane is parchment paper.

Question 22.
By which type of active transport, two different diffusible molecules are carried by a single carrier protein?
Answer:
In coupled transport, two different diffusible molecules are carried by a single carrier protein.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 23.
Name the components of xylem, which play a major role in the transport of water.
Answer:
The components of xylem, which play a major role in the transport of water are tracheid and trachea.

Short Questions and Answers : (2 marks for each question)

Question 1.
What is meant by transport?
Answer:
The process by which food materials, mineral salts, hormones and various gases reach the cells of living organisms and different harmful metabolic waste matters are sent from tissues to respective excretory organs through liquid medium, is called transport.

Question 2.
How is facilitated diffusion different from simple diffusion
Answer:
In facilitated diffusion, a carrier molecule or a channel protein in the membrane helps the entry of the diffusible molecules through it, but in simple diffusion, carrier protein is not required.

Question 3.
What is meant by passive transport?
Answer:
Passive transport is a process by which any molecule or ion of a substance passes through cell membrane along concentration gradient without consuming any metabolic energy. ExampleDiffusion and osmosis.

Question 4.
What is meant by active transport?
Answer:
Active transport is a process by which any molecule or ion needs some metabolic energy to pass through a cell membrane by the help of carrier protein, against concentration gradient. Example-Intake of glucose molecules by a cell.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 5.
What is diffusion?
Answer:
The physical process by which molecules or ions of any substance, moves from a region of higher concentration to a region of lower concentration, with the help of their own kinetic energy, is called diffusion. Example-Aroma of incense stick spreads to all corners of the room by diffusion.

Question 6.
What is meant by osmosis?
Answer:
If two solutions of different concentration, prepared from the same liquid solvent, are separated by a semi-permeable membrane, the solvent molecules move from the region of higher solvent concentration towards the region of lower solvent concentration, until equilibrium is attained. This physical phenomenon is known as osmosis. Example-Raisins swell in water due to osmosis.

Question 7.
What is meant by facilitated diffusion?
Answer:
Facilitated diffusion is a type of diffusion, where diffusible molecules pass through a cell membrane with the help of some channel proteins present in it. In this process, no metabolic energy is needed.
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 1

Question 8
What is meant by root pressure? Mention the importance of root pressure.
Answer:

  • Root pressure: The cumulative turgor pressure created in the cells, surrounding the xylem vessels of the root, due to absorption of sap is known as root pressure.
  • Importance: Root pressure pushes the sap into the xylem vessels through their thick cell wall and drives the sap upward.

Question 9.
What is cohesive force? What is meant by adhesive force.
Answer:

  • Cohesive force: The force of attraction between two particles or molecules of a same substance, is called cohesion force. Inside the xylem vessels water droplets remain attached to each other by cohesive force.
  • Adhesive force: The force of attraction between the particles of different substances, is called the adhesive force. The water droplets remain attached to the wall of xylem vessel by adhesive force.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 10.
What is transpiration pull?
Answer:
In xylem vessels, uninterrupted water column is formed by cohesive-adhesive force. These columns extend from the roots to the stomata of the leaves. During transpiration, when a molecule of water leaves the stomatal opening, it applies an upward pulling force on the receding water column, which is known as transpiration pull.

Question 11.
What is meant by ascent of sap?
Answer:
The transport of water and minerals, known as sap, from root to the leaves through xylem vessels against the force of gravity, is known as the ascent of sap.

Question 12.
The fragrance of a perfume, sprayed at one corner of a room, can be felt in the entire room after some time. Which phenomenon is responsible for this?
Answer:
The fragrance of a perfume, sprayed at one corner of a room, can be felt in the entire room after some time due to a phenomenon called diffusion.

Question 13.
Name the forces which control the ascent of sap in plants.
Answer:
The forces which control the ascent of sap in plants are-

  • root pressure
  • transpiration pull
  • adhesive force and
  • cohesive force.

Question 14.
Give two examples of liquid-liquid diffusion.
Answer:
Two examples of liquid-liquid diffusion are-
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 2

  • Diffusion between water and ink and
  • Diffusion between water and sugar syrup.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 15.
Give two examples of liquid-solid diffusion.
Answer:
Two examples of liquid-solid diffusion are-
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 3

  • Diffusion between water and sugar crystal and
  • Diffusion between water and copper sulphate (CuSO4)crystals.

Question 16.
Give two examples of solid-gas diffusion.
Answer:
Two examples of solid-gas diffusion are-

  • Diffusion between asafoetida and air and
  • Diffusion between camphor and air.

Question 17.
Give two examples of gas-gas diffusion.
Answer:
Two examples of gas-gas diffusion are-
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 4

  • Diffusion between air and ammonia gas and
  • Diffusion between air and smoke of inscence stick.

Question 18.
Mention two examples of carrier proteins which help in active transport.
Answer:
Two examples of carrier proteins which help in active transport are-

  • Sodium-Potassium pump (Na+/K+-ATPase pump) and
  • Proton pump (H- ATPase pump).

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 19.
Define hypertonic solution.
Answer:
A solution that has a higher concentration of solutes on the outer side of a cell in comparison to the inner side of it, is known as a hypertonic solution.
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 5

Question 20.
What is an isotonic solution?
Answer:
A solution that has identical concentration of solutes on both outer and inner side of a cell, is known as isotonic solution.
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 6

Question 21.
Define a hypotonic solution.
Answer:
A solution that has lower concentration of solutes on the outer side of a cell in comparison to the inner side of it, is known as hypotonic solution.
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 7

Question 22.
What is absorption in plants?
Answer:
The physical process by which water and mineral salts enter the plant body through root hair by the process of endosmosis, is called absorption.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 23
Why the water potential of any solution is always negative?
Answer:
The water potential of pure water is zero. Thus, solute mixed any solution always has negative water potential.

Question 24.
What are the major components of pholem sap?
Answer:
The major components of pholem sap arecarbohydrate, amino acid, minerals and organic acid and water.

Question 25.
Mention the differences between active transport and passive transport.
Answer:

Feature Active transport Passive transport
1. Metabolic Energy Cellular metabolic energy is requried Cellular metabolic energy is not required
2. Enzymes Play important role Play no role
3. Transpiration pull Plays no role Plays major role
4. Effect of O2 Transport is hampered in the absence of free O2 Transport is not effected by the absence of free O2

Question 26.
Mention the differences between diffusion and osmosis.
Answer:

Feature Diffusion Osmosis
1. Semi-permeable membrane Not necessary for diffusion Essential for osmosis
2. Medium Occurs between different media (solid, liquid, gas) Occurs between two liquids
3. Transportability Both solute and solvent are transported Only solvents are transported


Long Questions and Answers : (5 marks for each question)

Question 1.
Mention the role of different factors in controlling diffusion.
Answer:
Role of different factors in controlling diffusion

Various factors play important role in controlling the rate of diffusion. These are mentioned below.

1. Temperature: With the increase in temperature of the medium, movement of diffusible molecules increase. Therefore, increase in temperature enhances the rate of diffusion.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

2. Size of diffusible molecules: Larger size of the diffusible molecules restricts their movement. Therefore, larger molecules show slower diffusion rate.

3. Extent of concentration gradient: Rate of diffusion also depends upon the concentration gradient of molecules of both media. The greater the difference in concentration, the more rapid the diffusion. The closer the distribution of both molecules gets to equilibrium, the slower the rate of diffusion becomes.

4. Solubility: A molecule with higher rate of solubility, diffuses quickly in a given medium.

5. Viscosity of the medium: The rate of diffusion is inversely proportional to the viscosity of the medium. That is, if the viscosity of the medium is high, then the rate of diffusion will be lower and vice versa.

Question 2.
Mention the salient features of diffusion. Give two examples of diffusion in plants.
Answer:
The salient features of diffusion:
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 8
The salient features of diffusion are as follows—

  • Diffusible molecules of solid, liquid or gaseous substances can diffuse within either liquid or in gaseous medium.
  • Diffusible molecules move from a region of higher concentration to a region of lower concentration.
  • Diffusion of molecules continues until homogeneity’ is attained, i.e. the concentration of molecules in both directions becomes same.
  • It is a passive process, i.e. does not require any metabolic energy.

Example of diffusion in plants
Two examples of diffusion in plants are —

  • passive absorption of ions and
  • absorption of O and CO2 in cells.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 3.
What is meant by plasmolysis and deplasmotysis? What happens when a living cell is placed in a solution with concentration identical to its protoplasm?
Answer:
Plasmolysis:
If a cell with intact cell membrane is placed in a hypertonic solution, i.e. a solution with concentration higher than the concentration of the protoplasm of the cell, water from the protoplasm will gradually move out from the ceil through its cell membrane by exosmosis. In this case the protoplasm of the cell will shrink and the cell will appear wrrinkied. This phenomenon is called plasmolysis.

Deplasmolysis
If a plasmolysed cell is placed in a hypotonic solution, i.e. a solution with concentration lower than the concentration of the protoplasm of the cell, water from the outer medium will enter into the protoplasm through the cell membrane by endosmosis. In this case, the protoplasm will get more water and the cell will be distended. This phenomenon is called deplasmolysis.

Fate of living cell in isotonic solution
If a living cell is placed in a solution with concentration identical to its protoplasm, i.e., isotonic solution, water from outer medium and from the protoplasm will move through the cell membrane at same rate against each other. Therefore, no change will appear in the cell.

Question 4.
Mention the salient features of osmosis. Mention three roles of osmosis in plant body.
Answer:
The salient features of osmosis:
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 9
The salient features of osmosis have been mentioned below.

  • Osmosis occurs only in liquid medium.
  • This process involves the presence of semi-permeable membrane.
  • Solvent molecules move from a region of its higher concentration to a region of lower concentration across the semi-permeable membrane. Movement of solutes does not occur in osmosis.
  • Movement of solvent molecules continues until homogeneity is attained. In osmosis, rate of movement of solvent molecules on either side of the semi-permeable membrane becomes the same.
  • It is a passive process, i.e. does not require any metabolic energy.

Role of osmosis in plant body
In plants, osmosis helps in-

  • absorption of water,
  • opening and closing of the stomata and
  • maintaining turgidity of cell.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 5
Briefly describe the characteristic features of active transport. Mention the importance of cell to cell transport.
Answer:
The characteristic features of active transport:

The characteristic features of active transport has been briefly described below.

  • In this process, the movement of substances occur from a region of lower concentration to a region of higher concentration.
  • The cell membrane has different carrier proteins that remain suspended in its lipid bi-layer. The substances to be transported, first bind to a specific carrier protein and then passes from one side of the membrane to another.
  • The movement of substances against the concentration gradient requires the involvement of energy, which is supplied by ATP. In plants, active transport occurs during absorption of mineral ions by plant roots, loading of sugar into the phloem etc.
  • Active transport requires a semi-permeable membrane.

Importance of cell to cell transport:
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 10
The importance of cell to cell transport are as follows

  • Diffusible materials like O2 ,CO2 etc. move from one cell to the next, by cell to cell diffusion.
  • Water passes from one cell to another, by cell to cell osmosis.
  • Sugar is loaded into the phloem cells from the leaf cells by means of cell to cell active transport.

Question 6.
How does ascent of sap occur in a plant?
Answer:
Ascent of sap:
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 11
Transpiration is the process that acts as a driving force for the ascent of sap, from roots to the top of a tree, via xylem vessels. The sequence of events during ascent of sap occurs in the following order:

  • Release of water through stomata by transpiration.
  • Lowering of turgor pressure of leaf cells due to loss of water.
  • Uptake of water by leaf cells from the xylem elements causing a vacuum in the xylem vessels.
  • Generation of a vertically upward suction force on the water column in the xylem vessel, called transpiration pull.
  • Cohesive and adhesive forces of water molecules maintain the uninterrupted water column within the xylem vessels.
  • Roots absorb water and minerals from the soil by imbibition and endosmosis, that moves through the endodermis and increases turgor pressure in the cells surrounding the xylem vessels.
  • The mounting root pressure pushes sap into xylem vessels and starts to drive it against gravity towards the leaves upwards.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

Question 7.
How is food transported in different parts of the plant body?
Answer:
Transportation of food in plant body:
WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases 12
Transportation of food in plants occurs through sieve tubes of phloem. The cells of selve tube are arranged one after the other forming a continuous structure. Regarding the mechanism of this process, ‘pressure flow hypothesis’ by Ernst Munch, is the most accepted one. According to this hypothesis, following events occur during food transport in plants.

1. Transfer of food from mesophyll tissue to sieve tube: In mesophyll tissues, glucose produced by photosynthesis is soon converted into a larger sugar (sucrose). The sucrose solution is then transferred to the sieve tube via bundle sheath cells, phloem parenchyma and companion cells by cell to cell transport.

2. Creation of pressure within sieve tube: With the entry of sucrose, the cytoplasm of sieve tube becomes denser. As a result, a concentration gradient develops between the sieve tube & neighbouring xylem vessels. Due to this, water moves into the sieve tube from xylem vessels by osmosis, thereby, creating additional pressure within the sieve tubes.

WBBSE Class 9 Life Science Solutions Chapter 3.1D Movement of Water, Minerals, Food and Gases

3. Flow of food: This mounting pressure produced within the sieve tube, pushes the food solution to different parts of the plant body. Finally, the sucrose solution enters into the tissue cells from the sieve tube.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Detailed explanations in West Bengal Board Class 9 Life Science Book Solutions Chapter 3.2B Cellular Level Respiration offer valuable context and analysis.

WBBSE Class 9 Science Chapter 3.2B Question Answer – Cellular Level Respiration

Very Short Questions and Answers : (1 mark for each question)

Question 1.
Which type of respiratory process generates energy inside the living cell?
Answer:
Internal or cellular respiration generates energy inside the living cell.

Question 2.
What is meant by respiratory substrate?
Answer:
The compounds, which are oxidised during cellular respiration to release energy, are known as respiratory substrates.

Question 3.
In which form does respiratory substrate liberate energy during cellular respiration?
Answer:
During cellular respiration, energy is liberated from respiratory substrate in the form of ATP.

Question 4.
Where do reactions of glycolysis take place during cellular respiration?
Answer:
Reactions of glycolysis take place in the cytoplasm during cellular respiration.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 5.
What is meant by glycolysis?
Answer:
The breakdown of glucose by enzymes, releasing energy and pyruvic acid, is called glycolysis.

Question 6.
How many pyruvic acid molecules are formed at the end of glycolysis?
Answer:
Two pyruvic acid molecules are formed at the end of glycolysis.

Question 7.
Where do the reactions of Krebs cycle take place?
Answer:
Reactions of Krebs cycle occur in the mitochondria.

Question 8.
Mention the by-products of Krebs cycle.
Answer:
The by-products of Krebs cycle are CO2, reduced NAD and FAD (i.e. NADH + H+ and FADH2 respectively).

Question 9.
Which reactions of respiration occur in the inner membrane of mitochondria?
Answer:
The reactions of electron transport system or terminal respiration occur in the inner membrane of mitochondria.

Question 10.
In which phase of aerobic respiration is ATP produced?
Answer:
ATP is produced by ETS (electron transport system) of aerobic respiration.

Question 11.
Mention two organic end-products of anaerobic respiration.
Answer:
Lactic acid and ethyl alcohol are two organic end-products of anaerobic respiration.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 12.
Name a type of animal tissue, where anaerobic respiration takes place.
Answer:
Anaerobic respiration occurs in the voluntary muscles of animals.

Question 13.
Which organic compound is formed in muscle cells due to anaerobic respiration?
Answer:
Lactic acid is formed in muscle cells due to anaerobic respiration.

Question 14.
Which organic compound is produced in plant cells due to anaerobic respiration?
Answer:
Ethyl alcohol is produced in plant cells by anaerobic respiration.

Question 15.
Which organic compound is produced by fermentation of milk?
Answer:
Lactic acid is produced by fermentation of milk.

Question 16.
Which organic compound is produced by fermentation of glucose or sucrose in oxygen free condition?
Answer:
Ethyl alcohol is produced by fermentation of glucose or sucrose in oxygen free condition.

Question 17.
Name an enzyme present in yeast, wihch helps in aicoholic fermentation of sugar solution.
Answer:
Enzyme zymase is present in yeast, which helps in alcoholic fermentation of sugar solution.

Question 18.
Which enzyme, present in Lactobacillus, helps in fermentation of milk-sugar?
Answer:
Lactate dehydrogenase is the enzyme, present in Lactobacillus, which helps in fermentation of milk-sugar.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 19.
Where does aerobic respiration take place?
Answer:
Aerobic respiration takes place in all organisms living in air, water and soil in contact with free molecular oxygen.

Question 20.
How many high energy bonds are present in ATP?
Answer:
Two high energy bonds are present in ATP.

Question 21.
How much energy is released during hydrolysis of 1 molecule of ATP?
Answer:
During hydrolysis of 1 molecule of ATP, 7.3 kcal energy is released.

Question 22.
Which cell organelies are called ‘energy transducers’?
Answer:
Those cell organelles which convert one form of energy into another, are called ‘energy transducers’.

Question 23.
Name two organelles which act as energy transducers.
Answer:
Two organelles which act as energy transducers are chloroplast and mitochondrion.

Question 24.
Name the scientist who first observed the difference between respiration and combustion.
Answer:
Antoine Lavoisier first observed the difference between respiration and combustion.

Short Questions and Answers : (2 marks for each question)

Question 1.
What is respiration?
Answer:
Respiration is a catabolic process, which involves the intake of oxygen within cells and liberation of kinetic energy by oxidation of food or respiratory substrates, for performing different life activities.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 2.
What is meant by cellular respiration?
Answer:
The bio-chemical process by which food or respiratory substrates are oxidised within the cells to liberate kinetic energy in the form of ATP, is known as cellular respiration.

Question 3.
What is meant by aerobic respiration?
Answer:
Aerobic respiration is a type of cellular respiration, where respiratory substrate is oxidised completely in the presence of free oxygen to discharge carbon dioxide and water as by-products and to liberate the total energy from the substrate.

Question 4.
Write down the chemical equation of aerobic respiration.
Answer:
The chemical equation of aerobic respiration is mentioned below.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 1

Question 5.
What is meant by anaerobic respiration?
Answer:
Anaerobic respiration is a type of cellular respiration, where respiratory substrate is incompletely oxidised in absence of free molecular oxygen but by the help of the oxygen of inorganic compounds like \(\mathrm{NO}_3^{-}\) \(\mathrm{SO}_4^{2-}\), \(\mathrm{CO}_3^{2-}\), etc. to release carbon dioxide as by-products and to a little amount of energy from the substrate, along with organic compounds.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 6.
In which organisms anaerobic respiration occurs?
Answer:
Anaerobic respiration occurs in some bacteria such as Paracoccus denitrificans, Methanobacterium autotrophicum, Bacillus licheniformis etc., few fungi such as yeast, protozoa, all endoparasitic worms (Taenia, Ascaris, Echinococcus etc.). It also occurs in the seeds and few other cells of plants and voluntary muscle cells of animals.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 2

Question 7.
What is meant by fermentation?
Answer:
Fermentation is a typical anaerobic, enzymedependent process of incomplete oxidation of sugar, which produces different organic compounds (ethyl alcohol, lactic acid, butyric acid etc.) with partial liberation of energy from the respiratory substrate.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 3

Question 8.
Write down the chemical equation of ethyi alcohol fermentation.
Answer:
The chemical equation of ethyl alcohol fermentation is mentioned below.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 4

Question 9.
Write down the chemical equation of lactic acid fermentation.
Answer:
The chemical equation of lactic acid fermentation is as follows-

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 9

Question 10.
What is meant by alcoholic fermentation?
Answer:
Alcoholic fermentation is a special type of fermentation, where yeast (Saccharomyces) ferments sugar (glucose, fructose, sucrose etc.) solutions to produce ethyl alcohol with the help of a typical enzyme, zymase. In this process, CO2 and a little energy are also released.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 5

Question 11.
What is meant by lactic acid fermentation?
Answer:
The fermentation process, where certain bacteria (Lactobacillus) ferment milk-sugar (lactose), to produce lactic acid in absence of O2, liberating a little amount of energy ( 36 kcal ), called lactic acid fermentation.

Question 12.
What is glycolysis?
Answer:
Glycolysis is an oxygen-independent reaction, where glucose, within the cytoplasm of living cells, is broken into pyruvic acid molecules through a series of enzyme-mediated reactions and in this process produce NADH+H+, H2 O and ATP as by-products.

Question 13.
Why is glycolysis called EMP path?
Answer:
Scientists Embden, Meyerhof and Parnas discovered the reaction pathway of glycolysis. Therefore, after the first letter of the names of these three scientists, glycolysis is known as EMP path.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 14.
What is Krebs cycle?
Answer:
Krebs cycle is a cyclic reaction pathway, through which, acetyl Co-A, the decarboxylated end product of pyruvate (produced in glycolysis), is oxidised in steps to produce CO2 and H2 O and in this process, NAD and FAD are reduced to NADH+H+and FADH2 respectively. It is named after scientist Hans Krebs.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 6

Question 15.
Why is Krebs cycle known as TCA cycle and citric acid cycle?
Answer:
Citric acid is produced in the first step of Krebs cycle, therefore it is called Citric acid cycle. Citric acid contains three carboxylic groups, therefore, this cycle is also known as tricarboxylic acid cycle or TCA cycle.

Question 16.
What is meant by terminal respiration?
Answer:
Terminal respiration is the last step of aerobic respiration, where NADH+H+and FADH2, produced in giycolysis and Krebs cycle, are oxidised by electron carriers, situated in the inner membrane of mitochondria, and hydrogen is oxidised by the atmospheric oxygen to form water and piroduce ATP.

Question 17.
Mention the four phases involved in aerobic respiration.
Answer:
The four phases involved in aerobic respiration are-

  • glycolysis
  • oxidation of pyruvate
  • kerbs cycle
  • terminal respiration.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 18.
What is ATP synthases?
Answer:
ATP synthase is a enzyme, present on the inner membrane of mitochondria and helps in the synthesis of ATP.

Question 19.
How does organ-level respiration differs from cellular respiration?
Answer:

Features Organ level respination Cellatar respiration
1. Nature of reaction It is a physical process It is bio-chemical process
2. Site of respiration Different respiratory organs are involved All living cells are involved
3. Occurence of chemical reaction No chemical reaction occurs Various chemical reactions occur
4. Steps involved Inspiration, gaseous exchange and expiration Glycolysis, Krebs cycle and terminal respiration

Question 20.
Distinguish between glycolysis and Krebs cycle.
Answer:

Features Glycolysis Krebs cycle
1. Occurrence Cytoplasm Mitochondria
2. Entry-level substrate Glucose Acetyl Co-A
3. Reaction path Straight Circular
4. End product Pyruvate, ATP, NADH + H+ CO2, NADH + H+, FADH2 and GTP

Question 21.
Distinguish between combustion and respiration.
Answer:

Features Combustion Respiration
1. Nature of reaction Physico-chemical process Bio-chemical process
2. Enzymes No role Plays essential role
3. Free oxygen Essential May occur in absence of oxygen
4. Regulation of oxidation Very fast and not controlled Slow and controlled
5. Energy generated Heat and light energy Only heat energy

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 22.
Distinguish between alcoholic fermentation and lactic acid fermentation.
Answer:

Features Alcoholic fermentation Lactic acid fermentation
1. Occurence Occurs in yeast cell Occurs in voluntary muscles and certain bacterial cells
2. CO2 production Occurs Does not occur
3. End-products Ethyl alcohol Lactic acid

Long Questions and Answers : (5 marks for each question)

Question 1.
Briefly describe the process of glycolysis with the help of a schematic diagram.
Answer:
Glycolysis
Glycolysis is the primary step of cellular respiration occurring in cytoplasm of all living cells. By this process, glucose is enzymatically broken into two pyruvic acids (3C) through a straight chain reaction path. Each step requires a specific enzyme which acts as biocatalyst.
In this metabolic process, glucose is first converted into glucose 6-phosphate and then to fructose 1, 6-bisphosphate. In this phase, two ATP molecules are consumed. In the next step, this fructose

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 7

1, 6-bisphosphate is broken into two 3C compounds-glycerabldehyde 3-phosphate and dihydroxyacetone phosphate. Enzymatically, this dihydroxyacetone phosphate is transformed into glyceraldehyde 3 phosphate. At the final phase, two molecules of glyceraldehyde 3phosphate transforms step-by-step to form two molecules of pyruvic acid. By glycolytic breakdown of one molecule of glucose, four ATP molecules are produced and two are consumed, therefore, two ATP molecules are net gained. In this reaction, two molecules of NADH + H+ are also produced.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 2.
Briefly describe the reaction process of Krebs cycle with the help of schematic diagram.
Answer:
Krebs cycle

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 8

Krebs cycle is the second major phase of aerobic respiration. This reaction occurs in the mitochondria in a cyclic reaction path, where a 6 carbon substrate, citric acid is converted step-by-step into 5 C and 4 C substrates. The entry-level substrate of Krebs cycle is acetyl Co-A, which is produced from pyruvic acid, the end product of glycolysis. In Krebs cycle, acetyl Co-A and oxaloacetic acid combine to form citric acid. This is the initial product of this cycle.

In this process CO2, is released in steps. The other products are NADH+H+, FADH2 and GTP. This GTP is transformed into ATP directly. The other two products NADH+H+ and FADH2 are oxidised by dissociation of hydrogen through electron transport system.

Question 3.
Mame the enzyme present in the oxysomes of mitochondria. How does terminal respiration occur in a cell of any aerobic organism? 1 + 4
Answer:
Enzyme in oxysome
ATP synthetase enzyme is present in the oxysomes of mitochondria.

Terminal respiration
Terminal respiration is the final phase of aerobic reaction, which involves the production of ATP and H2 O. This is the energy generating, i.e., ATP producing final phase of cellular respiration. NADH + H+ and FADH2, (reduced hydrogen carriers) which are produced during glycolysis, decarboxylation of pyruvic acid & Krebs cycle, are oxidised in this reaction path. At first, hydrogen atoms are released from NADH + H+ and FADH2. Then each hydrogen atom releases one electron, which is then transported by iron containing electron carriers cytochrome. This process generates huge chemical energy, which finally produces energy-rich ATP molecules. So, this reaction pathway is also known as electron transport system or ETS. The hydrogen atoms, released from NADH+ H+ and FADH2 finally react with O2 present in the atmosphere to produce H2 O.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 4.
Mention the significance of respiration.
Answer:
Significance of respiration
The significance of respiration are mentioned below.
1. Conversion of energy and ATP production: The potential energy stored in food, is converted into kinetic energy by respiration. This energy is dissipated as heat and some portion of it is stored in ATP within the cells, as chemical energy for future use.

2. Maintenance of O2-CO2 balance: During respiration, atmospheric oxygen is consumed and carbon dioxide is released. Whereas, photosynthesis does the opposite. Thus, photosynthesis and respiration jointly maintain the balance of oxygen and carbon dioxide in the environment.

3. Economic importance: Fermentation of flour (starch) by yeast makes cakes and breads puffy. Ethyl alcohol is a fermentation product, which has great economic importance for medicinal purpose and to prepare alcoholic beverages. Cheese, butter, curds are prepared by fermentation of milk. Some vitamins like vit B1, vit B12, vit C etc. are also produced in the body by bacterial fermentation.

4. Excretion: Various excretory products like ammonia, ketone body, alcohol, water vapour, volatile fatty acids, etc., are given out of the body through respiration.

5. Maintenance of Acid-Base balance: Since CO2 is liberated during respiration, it helps to maintain acid-base balance in the body.

6. Regulation of temperature: When animals exhale, certain amount of heat is liberated from their bodies, thus regulating the temperature of the body.

7. Light generation: Certain deep-sea animals, like Ctenophorans and insects, like fireflies can generate light. This phenomenon is called bioluminescence. This light is generated from the chemical energy, gained by respiration.

8. Electrical power generation: Some fishes like Torpedo and electric eel can generate huge electrical power within their electric organs to kill preys. Respiration produces this power from chemical energy.

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration

Question 5.
Compare among aerobic respiration, anaerobic respiration and fermentation.
Answer:
Comparison among aerobic respiration, anaerobic respiration and fermentation
WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 10

Question 6.
Distinguish between photosynthesis and respiration.
Answer:
Differences between photosynthesis and respiration

WBBSE Class 9 Life Science Solutions Chapter 3.2B Cellular Level Respiration 11

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Detailed explanations in West Bengal Board Class 9 Life Science Book Solutions Chapter 3.1C Transpiration offer valuable context and analysis.

WBBSE Class 9 Science Chapter 3.1C Question Answer – Transpiration

Very Short Questions and Answers : (1 mark for each question)

Question 1.
Which tiny pores, present on the leaf surface help in gaseous exchange and liberation of excess water as vapour?
Answer:
Stomata are the tiny pores, present on the leaf surface, helping in gaseous exchange and liberation of excess water as vapour.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 2.
Which cells control the opening and closing of stomata?
Answer:
Guard cells control the opening and closing of stomata.

Question 3.
Name the small lens-shaped pores present on the stems of plants, which serve as site of transpiration.
Answer:
The small lens-shaped pores present on the stems of plants, which serve as site of transpiration, are called lenticels.

Question 4.
Which layer on the leaf surface prevents transpiration in desert plants?
Answer:
Cuticle layer on the leaf surface prevents transpiration in desert plants.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 5.
At which time of a day does transpiration occurs at the maximum rate?
Answer:
During mid-day, transpiration occurs at the maximum rate.

Question 6.
Why does transpiration occur mainly during the daytime?
Answer:
Light helps in opening of the stomata, therefore, transpiration occurs mainly during the daytime.

Question 7.
In which type of plants do stomata open at night?
Answer:
In some desert plants stomata open at night.

Question 8.
Why do stomata of some desert plants open at night?
Answer:
To prevent excess water loss during daytime, stomata of some desert plants open at night.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 9.
In lotus, on which surface of the leaf are stomata present?
Answer:
In lotus, stomata are present on the dorsal surface of the leaf.

Question 10.
In which season of the year does transpiration in terrestrial plants reaches the peak?
Answer:
In dry summer season, transpiration in terrestrial plants reaches the peak.

Question 11.
Why are the leaves of many desert plants modified into spines?
Answer:
The leaves of many desert plants are modified into spines in order to prevent water loss by transpiration.

Question 12.
Why do many desert plants possess dense hairs on the body surface?
Answer:
Dense hairs prevent direct air contact on leaf surface and thus, reduce the rate of transpiration, therefore, many desert plants possess dense hairs on the body surface.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 13.
How does air flow affect the rate of transpiration?
Answer:
Rate of transpiration increases with the increase in air flow.

Question 14.
Why is the rate of transpiration low in pine leaves?
Answer:
Needle-shaped pine leaves possess lesser number of stomata, which are slightly sunken in nature, so rate of transpiration is low in pine leaves.

Question 15.
Which instrument is used to measure the rate of transpiration?
Answer:
Ganong’s potometer is used to measure the rate of transpiration.

Question 16.
Why is rate of transpiration higher on the ventral surface of the leaves of dicotyledonous plants?
Answer:
Leaves of dicotyledonous plants possess more stomata on the ventral surface, therefore, the rate of transpiration is higher on that side.

Question 17.
Mention the phenomenon through which plants give out excess water in the form of droplets?
Answer:
The phenomenon through which plants give out excess water in the form of droplets, is known as guttation.

Question 18.
In which side of an isobilateral leaf, do we find more number of stomata?
Answer:
In an isobilateral leaf, stomata are distributed equally on both sides of the leaf.

Question 19.
How is the rate of transpiration affected on a rainy day?
Answer:
Since the percentage of water vapour is high in the atmosphere on a rainy day, the rate of transpiration decreases.

Short Questions and Answers : (2 marks for each question)

Question 1.
How do guard cells control the opening and closing of stomata?
Answer:
In the presence of light, hygroscopic pressure increases inside the guard cells. Due to unequal elasticity of cell walls of the two opposite sides of each guard cell, the cells bend like beans. As a result, the space between two guard cells widens to open the stomata. In the absence of light, hygroscopic pressure decreases inside the guard cells and the stomata close.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 2.
Why is the stomata of lotus plant present on the dersal surface of the leaves?
Answer:
The lotus leaves float on the water surface and the stomata are present on the dorsal surface to keep direct contact with air. This typical placement of stomata helps lotus leaves to maintain gaseous exchange with atmosphere and thus, perform transpiration.
WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 1

Therefore, a plant with wider leaves shows higher rate of transpiration than a plant with narrow leaves. Also, in some plants (e.g. cactus) leaves are modified into spines to reduce transpiration. Thus, shape of leaves influence the rate of transpiration.

Question 3.
Why do plants with wider leaves wilt in summer but a pine tree remains unaffected?
Answer:
Plants with wider leaves have more number of stomata, through which they lose excess water in form of vapours due to transpiration on summer days. This loss of water makes the cells turgid and the protoplasm shrinks. This results into wilting of these plants. Whereas, a pine tree possesses needle-like leaves with very little number of sunken stomata. Therefore, pine trees lose much less water by transpiration and remain unaffected even on a summer day.

Question 4.
Why is transpiration called a necessary evil?
Answer:
Transpiration helps plants in the ascent of sap, removal of excess water, cooling the plant body, maintaining the water balance. On the other hand, excessive transpiration causes decrease in protoplasmic water content and thus, resulting into shrinkage of cells followed by wilting of leaves and tender branches. This is why, transpiration is called a necessary evil.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 5.
How does shape of leaves influence the rate of transpiration?
Answer:
Number of stomata is directly proportional to the rate of transpiration. A wider leaf has more stomata than a leaf with narrow leaf lamina. Therefore, a plant with wider leaves shows higher rate of transpiration than a plant with narrow leaves. Also, in some plants (e.g. cactus) leaves are modified into spines to reduce transpiration. Thus, shape of leaves influence the rate of transpiration.
WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 4

Question 6.
If all the leaves of a plant are applied with a layer of vaseline, what will happen to it?
Answer:
If all the leaves of a plant are applied with a layer of vaseline, the stomatal openings will be sealed completely. In this situation, the plants will not be able to carry out gaseous exchange for photosynthesis and respiration. The excess water in the plant body will not be expelled out. This will affect many necessary physiological activities of the cells and the cells will die and eventually the whole plant.

Question 7.
What is wilting?
Answer:
In case of excess transpiration during daytime in summer, the plants lose large amount of water. As a result, protoplasm of cells lose turgidity and shrink. Hence, leaves and tender branches droop. This is called wilting. If the whole plant wilts and remains in that state for several hours, it may die.
WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 2

Question 8.
How does transpiration control environmental condition?
Answer:
By transpiration, water vapour is released in the atmosphere. This increases the relative humidity, which in turn helps in the formation of clouds. Therefore, transpiration initiates rainfall in an area and thus, regulates atmospheric temperature and soil water content of that environment.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 9.
What are hydathodes? What is the function of hydathodes?
Answer:

  • Hydathodes: Several plants, specially herbs, possess small pores on the apices and edges of their leaves. These small pores are known as hydathodes.
  • Function: Hydathodes help the plants to dispose excess water from the body in the form of droplets, by a process called guttation but they do not take part in transpiration.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 3

Question 10.
State the relationship between transpiration and root-shoot ratio.
Answer:
The rate of transpiration is reduced if the rootshoot ratio is less i.e root system is less branched and less deep or shoot is larger in size.

Long Questions and Answers : (5 marks for each question)

Question 1.
What is transpiration? Mention the differences between transpiration and evaporation.
Answer:
Transpiration
Transpiration is a life process, by which terrestrial plants eliminate excess water from the aerial parts of the body in form of water vapour, into the atmosphere.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Differences between transpiration and evaporation

Features Transpiration Evaporation
1. Nature It is a physiological process It is a physical process
2. Occurrence Occurs in plants through stomata, lenticels and cuticle Occurs in any free surface
3. Factors Vapour pressure, diffusion pressure and osmotic pressure are the main controlling factors of this process Relative humidity and air current are the main controlling factors of this process
4. Rate It is a slow and controlled process It is a quick process

Question  2.
How do plants eliminate excess water from their body? Give the difference between transpiration and guttation.
Answer:
Elimination of excess water from plant body Plants release maximum amount of the excess water from their body in the form of water vapour by the process of transpiration. This occurs through the stomata, cuticular pores and lenticels. Some herbs dispose excess water as droplets through small pores, present at the edges of their leaves, called hydathodes. This process of disposal of water by plants is known as guttation.

Differences between transpiration and guttation

Features Transpiration Guttation
1. Disposition of mineral salts Excess water is given out in the form of vapour Excess water is given out in the form of small droplets
2. Site of occurrence Stomata, lenticels, cuticle Small pores on the edges of leaves, called hydathodes
3. Factors Mineral salts are not disposed in this process Mineral salts are disposed along with water in this process

Question 3.
Mention one difference between stomata and hydathodes. Give a brief account of different structures involved in transpiration of plants.
Answer:
Difference between stomata and hydathodes:
One difference between stomata and hydathodes is that, stomata usually, open during the day and remain closed during the night (and in some desert plants, like Aloe vera, remain closed during the day, and open during the night). Whereas, hydathodes remain open all the time.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 5

Different structures involved in transpiration:
Transpiration occurs through three different parts of plant body-stomata, lenticels and cuticle. Based on this, the process is divided into the following types.

1. Stomatal transpiration: Stomata are small pores, present mainly on leaves and a few other parts of tender shoot. Each of these pores is surrounded by two guard cells, that help to open the stomatal pores during the day and close at night. Maximum amount of excess water (about 90-97% ) is eliminated through the stomata.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

2. Cuticular transpiration: Cuticle is a layer of waxy coating present on the epidermis of leaves. Very little amount of water (about 3-10% ) is eliminated through the minute pores of the cuticle.

3. Cuticular transpiration: Cuticle is a layer of waxy coating present on the epidermis of leaves. Very little amout of water (about 3-10%) is eliminated through the minute pores of the cuticle.

3 Lenticular transpiration: Lenticels are permanent, minute lens-shaped pores, found on the cracked bark of the trees. Negligible amount of water (about 0.1% ) is eliminated through these pores.

Question 4.
Mention the roles of different external factors regulating the rate of transpiration.
Answer:
External factors regulating transpiration
Various external factors control the rate of transpiration. These are discussed below.

1. Intensity of light: The most important external factor which regulates the rate of transpiration is the intensity of light. Stomata open during daylight in the presence of light and close at night. Thus, light controls transpiration by regulating the opening and closing of stomata. Increase in the intensity of light, increases the rate of transpiration. But decrease in light intensity decreases the rate of transpiration.

2. Temperature: Rate of transpiration increases with the rise in temperature. But when temperature rises above 35°C, the stomata start closing, in order to prevent excess water loss.

3. Humidity: Increase in relative humidity decreases the rate of transpiration and decrease in relative humidity increases transpiration rate. Therefore, transpiration is inversely proportional to the rate of humidity.

4. Wind flow: In airy environment, transpiration occurs at a faster rate. Therefore, wind flow is directly proportional to the rate of transpiration.

5. Density of carbon dioxide: Rate of transpiration also depends on the density of CO2 in the atmosphere. When density of CO2 increases and more CO2 accumulates in leaves, stomatal pores close, and rate of transpiration decreases and when density of CO2 is less, rate of transpiration increases. Thus, density of CO2 in the atmosphere is inversely proportional to the rate of transpiration.

Question 5.
Mention the roles of different internal factors regulating the rate of transpiration.
Answer:
Internal factors regulating transpiration
Various internal factors control the process of transpiration. These are discussed below.

1. Surface area and number of stomata in the leaves: Leaves with larger surface area possess more number of stomata. Therefore, transpiration rate is higher in plants with broader and larger leaves.

2. Size of stomata: Size of stomata is directly proportional to the rate of transpiration of a plant.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

3. Position of stomata: Stomata, present on the surface of leaves, facilitate transpiration, but in some plants, stomata is slightly sunken below the surface of leaves. This type of stomata helps to reduce the rate of transpiration.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 6

4. Cuticle: A plant with thick and waxy cuticle reduces cuticular transpiration. On the other hand, a thin and porous cuticle enhances transpiration rate.

5. Age of leaves: In older leaves, many stomata become clogged. So age of leaves is inversely proportional to the rate of transpiration.

6. Protoplasm: Increased density of cellular protoplasm results in an increase in the rate of transpiration and vice versa. Thus, density of protoplasm in the cell is directly proportional to the rate of transpiration.

7. Presence of hormones: Hormones such as abscisic acid control the rate of transpiration by regulating the opening and closing of stomata.

WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration

Question 6.
Explain the beneficial effects of transpiration. Mention its harmful effects.
Answer:
Beneficial effects of transpiration
The beneficial effects of transpiration are as follows-

  • Ascent of sap: Transpiration results in transpiration pull by which water and minerals reach the top leaves of the trees.
  • Elimination of excess water: By transpiration, excess water from the plant body is removed. It eases the physiological activities within the cells.
  • Cooling plant body: By this process, latent heat of evaporation is lost from the plant body, which cools the plant.
  • Maintaining water balance: Due to the removal of excess water from plant body, water balance is maintained within it.

Harmful effects of transpiration:
WBBSE Class 9 Life Science Solutions Chapter 3.1C Transpiration 7
The harmful effects of transpiration are as follows-

  • Drying of leaves and twigs: Excess transpiration reduces water content in plant cells. As a result, leaves and softer parts of plants become dry.
  • Wilting: In case of excess transpiration, the cells loseturgidity and shrink. Hence, leaves and tender branches droop. This is called wilting. If the whole plant wilts and remains in that state for several hours, it may die.
  • Wastage of energy: Plant utilises only about 5% of the total absorbed water for various functions of its body. The rest (about 95% ) is given out by transpiration. Thus, there is a wastage of energy.
  • Inhibition of gaseous exchange: Due to excess stomatal transpiration, gaseous exchange during photosynthesis and respiration through stomata, is inhibited.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Detailed explanations in West Bengal Board Class 9 Life Science Book Solutions Chapter 3.1B Mineral Nutrition offer valuable context and analysis.

WBBSE Class 9 Science Chapter 3.1B Question Answer – Mineral Nutrition

Very Short Questions and Answers : (1 mark for each question)

Question 1.
Which type of nutrients mainly take part in the structural formation of protoplasm?
Answer:
Macronutrients take part mainly in the structural formation of protoplasm.

Question 2.
Which type of elements act mainly as cofactors of enzymes?
Answer:
Micro elements mainly act as cofactors of enzymes.

Question 3.
What is the functional similarity between Fe and Cu in the life process of an organism?
Answer:
Both Fe and Cu take part in oxidation reduction process of photosynthesis and respiration.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 4.
What is the functional similarity between Zn and Mg in biochemical activities?
Answer:
Both Zn and Mg act as cofactors of enzymes.

Question 5.
What is chlorosis?
Answer:
The yellowing of leaves due to disintegration of chlorophyll, as a result of the absence of one or more essential elements, is called chlorosis.

Question 6.
Which metallic element is actively present in electron carriers like cytochrome and ferredoxin?
Answer:
Iron (Fe) is actively present in electron carriers like cytochrome and ferredoxin.

Question 7.
Mention a deficiency symptom of sulphur in patients.
Answer:
In case of sulphur deficiency, young twigs become weak.

Question 8.
Mention one metallic macronutrient and one micronutrient, essential for plants.
Answer:
Magnesium is a metallic macronutrient and iron is a metallic micronutrient, essential for plants.

Question 9.
Name any two gaseous macroelements essential for all living organisms.
Answer:
Oxygen and nitrogen are two gaseous macroelements essential for all living organisms.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 10.
Which macroelements take part in the structural formation of protoplasm?
Answer:
The macroelements which take part in the structural formation of protoplasm are C, H, O, N, P, Mg, and S.

Question 11.
Which macronutrient is essential for the formation of plasma membrane?
Answer:
Calcium is an essential macronutrient which helps in the formation of plasma membrane.

Short Questions and Answers : (2 marks for each question)

Question 1.
What is meant by macronutrients?
Answer:
The elements, that are required in larger quantities for growth, development and normal physiological activities of plants, are called macronutrients. Example-Carbon (C), Nitrogen (N), Phosphorus (P) etc.

Question 2.
What is meant by micronutrients?
Answer:
The elements, that are required in minute quantities for normal physiological activities of plants, are called micronutrients. Example – Molybdenum (Mo), Boron (B), Zinc (Zn) etc.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 3.
How are mineral nutrients associated with survival of plants?
Answer:
For normal growth, proper formation of cells and tissues and proper operation of all physiological functions, plants need different minerals. Minerals act as structural components of protoplasm, cofactors of various enzymes controlling several bio-chemical reactions within the cells etc. That is how mineral nutrients are associated with the survival of plants.

Question 4.
How do different elements take part in the formation of a plant cell?
Answer:
Various elements, such as C, H, O, S, Mg, P, N and Fe, play a prominent role in the formation of protoplasmic chemical constituents of a cell. All cellular matters are basically composed of carbon (C), hydrogen (H), oxygen (O), and nitrogen (N). Proteins need sulphur (S), nucleic acids need phosphorus (P), chlorophylls need magnesium (Mg) and middle lamella of cell needs calcium (Ca) other than C, H, O, and N.

Question 5.
Which elements play role in maintaining osmotic balance in plant cells?
Answer:
Different inorganic salts of potassium (K)and sodium (Na) play an important role in maintaining the osmotic balance of the cells in plants. The elements remain as chloride \(\left(\mathrm{Cl}^{-}\right)\), phosphate \(\left(\mathrm{PO}_4^{3-}\right)\), sulphate \(\left(\mathrm{SO}_4^{2-}\right)\) etc. which help to maintain the osmotic concentration within the plant cells.

Question 6.
How do salts play role in maintaining the pH of a cellular fluid?
Answer:
Certain ions, like phosphate \(\left(\mathrm{PO}_4^{3-}\right)\), bicarbonate \(\left(\mathrm{HCO}_3^{-}\right)\) and carbonate \(\left(\mathrm{CO}_3^{2-}\right)\) may act as buffers and thus resist marked change in pH. Thus, inorganic salts help to regulate pH of any cellular fluid.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 7.
What are the main functions of potassium in a plant body?
Answer:
The main functions of potassium in a plant body are as follows-

  • It takes part in protein and carbohydrate synthesis.
  • It acts as co-enzyme and helps in stomatal movement.
  • Maintains normal growth and colour of the leaves.

Question 8.
What are the symptoms that occur due to the deficiency of potassium?
Answer:
The distinct symptoms that occur due to the deficiency of potassium are-

  • discolouration of leaves,
  • slow growth of roots and seeds
  • curling of older leaves.

Question 9
Mention three importance of phosphorus in a plant body.
Answer:
Three importance of phosphorus in a plant body are as follows-

  • It plays an important role in protein synthesis.
  • It acts as component of ATP, NADP and membrane of cells and other organelles.
  • It prevents premature shedding of leaves and blackening of fruits and leaves.

Question 10
Mention the importance of calcium in a plant body.
Answer:
The importance of calcium in a plant body are as follows-

  • It helps in cell division by spindle formation and formation of middle lamella of the cell wall.
  • It helps in nitrogen and carbohydrate metabolism.
  • It maintains normal blooming of flowers.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 11.
What are the major roles of magnesium in a plant body?
Answer:
The main roles of magnesium in a plant body are as follows-

  • It acts as the metallic constituent of chlorophyll.
  • It acts as an enzyme activator.
  • Prevents scorching and discolouration of the leaves.

Question 12.
What are the significance of boron in a plant hody?
Answer:
The significance of boron in a plant body are as follows-

  • It helps in the formation and growth of leaves and flowers.
  • It takes part in calcium and potassium metabolism and protein synthesis,
  • It helps in the elongation of pollen tube.

Question 13.
What are the functions of zinc in plant body?
Answer:
The functions of zinc in plant body are as follows-

  • It helps in the synthesis of auxins and certain proteins.
  • It activates various enzymes as cofactors.
  • It also maintains normal growth of the stems and roots.

Question 14.
What are the symptoms that occur due to deficiency of zinc?
Answer:
The distinct symptoms that occur due to deficiency of zinc are-

  • retarded growth of roots, stems and leaves,
  • delayed seed formation,
  • discolouration of leaves.

Question 15.
What is the importance of manganese in a plant body?
Answer:
Importance of manganese in a plant body are as follows-

  • It acts as an enzyme activator.
  • It takes part in the chlorophyll and protein synthesis.
  • It helps in the normal growth of shoots and prevents necrosis of leaves.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 16.
Mention the significance of sulphur as a mineral nutrient.
Answer:
The significance of sulphur are as follows:

  • It acts as a major constituent of amino acids, vitamins and co-enzyme A.
  • It helps in the formation of chlorophylls and development of roots.
  • Sulphur prevents hardening of stems and helps in metabolism.

Question 17.
What is necrosis?
Answer:
The death of cells of certain areas of the plant body, due to the deficiency of any particular mineral nutrient (mainly Cl, Mn, Cu ) resulting in the drying up of those affected areas, is called necrosis.

Question 18.
Name the metallic elements which are essential for plants.
Answer:
The metallic elements which are essential for plants are-Magnesium (Mg), Potassium (K), Calcium (Ca), Manganese (Mn), Iron (Fe), Zinc (Zn), Copper (Cu), Molybdenum (Mo), Cobalt (Co), Nickel (Ni), Sodium (Na) etc.

Question 19.
Write the source of carbon (C), oxygen (O) and hydrogen (H) in plants.
Answer:
In plant body, source of carbon is the CO2 gas, present in atmosphere. Hydrogen is obtained from the water vapour present in atmosphere and also from the water present in soil. Oxygen is taken up by plants directly from the air.

Long Questions and Answers : (5 marks for each question)

Question 1.
Mention the general characteristic features of macronutrients. Write the characteristic features of micronutrients.
Answer:
Characteristic features of macronutrients
The general characteristic features of macronutrients are as follows-

  • These elements are present in larger quantities (1-10 mg per g dry weight of plants, or more).
  • They are mainly involved in the synthesis of structural components of the plant cells.
  • They also participate in maintaining the osmotic potential of the plants.

Characteristic features of micronutrients
The characteristic features of micronutrients are as follows-

  • The elements are present in minute quantities ( 0.1mg per g) dry weight of plant, or less).
  • High concentrations of micronutrients may prove to be toxic for the plants.
  • They mainly participate in electron transport mechanisms and act as cofactors for various enzymes.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 2.
Mention the general functions of different nutrients in plants.
Answer:
Functions of different nutrients in plants
The general functions of different nutrients in plants are as follows-

1. Formation of protoplast: Various nutrients, such as C, H, O, S, N, P, Mg and Fe play a prominent role in the formation of chemical constituents of protoplasm.

2. Structure of enzyme: Nutrients, such as Ca, Mg, K, Zn, Cl, Cu, Ni etc. are involved in the formation of various enzymes or act as co-factors.

3. Oxidation-reduction reaction: Flement such as Fe and Cu, take part in electron transfer and thus, bring about oxidation-reduction reaction.

4. Osmotic balance: Presence of inorganic salts (such as \(\mathrm{Cl}^{-}, \mathrm{PO}_4^{3-}, \mathrm{SO}_4^{2-}\) etc.) in the cell sap are involved in maintaining the osmotic balance of the cell.

5. Formation of chlorophyll: Elements, such as O, N, H, C and Mig play a prominent role in the formation of chlorophyll. Iron (Fe) helps in this process.

6. Buffer effect: Certain salts, like phosphates, bicarbonates and carbonates may act as buffers and thus, resist marked change in pH.

7. Growth: Mineral elements, such as Zn, Mn, B etc, maintain normal growth of stem and root.

Question 3.
Mention the importance of any five macronutrients in plants.
Answer:
Importance of any five macronutrients in plants
The importance of any five macronutrients in plants have been discussed below.

1. Phosphorus (P):

  • Plays an important role in protein synthesis.
  • It acts as a component of ATP, NADP and membrane of cells & other organelles.
  • It prevents premature shedding of leaves, blackening of fruits & leaves.

2 Sulphur (S) :

  • It is the major constituent of certain amino acids, vitamins & co-enzyme A.
  • It helps in the formation of chlorophyll & development of roots.
  • It also prevents hardening of stems and plays important role in growth and metabolism.

3. Potassium (K):

  • It takes part in protein & carbohydrate synthesis.
  • It acts as co-enzyme & helps in the stomatal movement.
  • Potassium maintains normal growth & colour of leaves.

4. Calcium (Ca):

  • It helps in cell division by spindle formation,
  • It helps in nitrogen & carbohydrate metabolism.
  • It helps in formation of cell membrane and the middle lamella of cell wall in plants.

5. Magnesium (Mg):

  • It acts as primary metallic constituent of chlorophyll.
  • It helps in enzyme activation.
  • It prevents scorching discolouration of leaves.
  • It helps in nucleic acid synthesis and controls fat and carbohydrate metabolism.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 4.
Mention the deficiency symptoms of the macronutrients phosphorus, sulphur and magnesium in plants. Mention the deficiency symptoms of the micronutrients copper, manganese and boron in plants.
Answer:
Symptoms due to deficiency of P, S and Mg:
The deficiency symptoms of phosporus, sulphur and magnesium are as follows-
1. Phosphorus (P):

  • Leaves and stems turn bluish-green in colour,
  • necrosis occurs in leaves,
  • plants become weak and stunted.

2. Sulphur (S):

  • Curling of leaves occurs followed by necrosis,
  • nodule formation in leguminous plants is hampered,
  • overall growth of plant is hampered.

3. Magnesium (Mg):

  • Chlorosis of matured leaves occurs.
  • retarded growth of plants is seen,
  • carbohydrate formation is hampered.

Symptoms due to deficiency of Cu, Mn and B.

The deficiency symptoms of copper, manganese and boron are as follows-
1. Copper (Cu):

  • Necrosis occurs in tender leaves
  • nitrogen metabolism is hampered
  • dieback disease (rotting) occurs in the tender portions of stems.

2. Manganese (Mn):

  • Necrosis of leaves occurs
  • leaves become yellowish, and intervenous chlorosis takes place.

3. Boron (B):

  • Rotting of apical portions of stems and roots, followed by necrosis
  • margins of leaves dry up and as a result the leaves curl up
  • drought spot disease occurs in apples.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Question 5.
Mention the importance of different micronutrients in plants.
Answer:
Importance of different micronutrients in plants
The importance of different micronutrients in plants have been mentioned below.

1. Iron (Fe):

  • It helps in the formation of chlorophyll & chromatin reticulum.
  • It acts as structural element of electron carriers & helps in ion absorption.

2 Copper (Cu):

  • It acts as structural component of some enzymes & helps in reduction of nitrates.
  • It takes part in electron transportation in photosynthesis.
  • It prevents necrosis of leaves in cereals & pulses.

3. Molybdenum (M0):

  • It helps in the fixation & assimilation of nitrogen.
  • It acts as cofactor for enzymes involved in nitrogen fixation.
  • It helps in normal flowering & colouration of leaves.
  • [It also helps in protein synthesis.

4. Zinc (Zn):

  • It helps in the synthesis of auxins & certain proteins,
  • It activates various enzymes by acting as cofactor.

5. Manganese (Mn):

  • It acts as enzyme activator.
  • Takes part in chlorophyll & protein synthesis.
  • Prevents necrosis of leaves.

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

6 Boron (B):

  • It helps in the formation and growth of flowers & leaves.
  • Takes part in protein synthesis.
  • Boron helps in the metabolism of calcium and potassium.
  • It also helps in the elongation of pollen tube.

7. Chlorine (CI):

  • Chloride ions, in the cell sap, helps in maintaining the osmotic balance of the cell,
  • Helps in the opening and closing of stomata.
  • takes a passive role in photosynthesis.

8 Nickel (Ni):

  • Nickel is a component of some plant enzymes, most notably urease, which metabolises urea into ammonia.
  • It also acts as a catalyst of enzymes, that help legumes to fix nitrogen.

Question 6.
Distinguish between macronutrients and micronutrients.
Answer:
Differences between macronutrients and micronutrients

Features macronutrients micronutrients
1. Necessity These are needed in larger quantities for growth, development and different physiological activities of the cell These are needed in very small quantities for growth, development and different physiological activities of the cell
2. General function Building ceil and different protoplasmic components Mainly help in catalytic activities
3. Effect of deficiency Deficiency symptoms are very distinct and plants are adversely affected Deficiency symptoms are often indistinct and plants are slightly affected
4. Effect of excess intake Excess nutrients are disposed without causing serious harm Often cause harm to the plant
5. Example Oxygen, nitrogen, carbon etc. Boron, molybdenum, manganese etc.

Question 7.
What is ‘hydroponics’? Explain in a few sentences.
Answer:
Hydroponics
Hydroponics is defined as the subset of hydroculture and a method of growing plants using mineral nutrient solution, in water, but without soil.
WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition 5

WBBSE Class 9 Life Science Solutions Chapter 3.1B Mineral Nutrition

Explanation:
Plants require several metallic and non-metallic elements for their normal healthy growth. Plants acquire these essential elements usually from the soil. But, scientists have experimentally proved that soil is not essential for the growth of plants. Only solutions, rich in mineral nutrients, are enough for this process. Thus, the process of cultivation of plants by placing roots in liquid nutrient solution, rather than in soil, and then observing their growth, is called ‘hydroponics.’ It is also called soilless growth of plants.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Detailed explanations in West Bengal Board Class 9 Life Science Book Solutions Chapter 3.3 Nutrition offer valuable context and analysis.

WBBSE Class 9 Science Chapter 3.3 Question Answer – Nutrition

Very Short Questions and Answers : (1 mark for each question)

Question 1.
Which physiological process provides potential energy to living organisms?
Answer:
Nutrition provides potential energy to living organisms.

Question 2.
Which two steps are involved in the nutrition of green plants?
Answer:
Photosynthesis and assimilation are involved in the nutrition of green plants.

Question 3.
How much energy is necessary for a healthy adult to perform the daily life activities?
Answer:
To perform all life activities, a healthy adult requires 2500-3000 kcal energy.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 4.
How much heat is liberated by complete oxidation of one gram of glucose?
Answer:
About 4.1 kcal energy is liberated by the complete oxidation of one gram of glucose.

Question 5.
How much heat is liberated by complete oxidation of one gram of protein?
Answer:
About 4.1 kcal energy is liberated by complete oxidation of one gram of protein.

Question 6.
How much heat is liberated by complete oxidation of one gram of fat?
Answer:
About 9.3 kcal energy is liberated by complete oxidation of one gram of fat.

Question 7.
Which component of food develops disease resistance?
Answer:
Vitamins develop disease resistance.

Question 8.
What is the similarity between Rafflesia and louse?
Answer:
Both Rafflesia and louse are parasitic in nature.

Question 9.
What is the similarity between Mycorrhiza and Rhizobium?
Answer:
Both Mycorrhiza and Rhizobium develop symbiotic association with flowering plants.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 10.
In which type of nutrition is one member benefited at the expense of another?
Answer:
In parasitic nutrition one member is benefited at the expense of the another.

Question 11.
What is the similarity between dung beetle and pig?
Answer:
Both dung beetle and pig show coprophagy.

Question 12.
What is the nutritional dissimilarity between louse and tapeworm?
Answer:
Louse is an ectoparasite but tapeworm is an endoparasite.

Question 13.
In which nutritional association both associates are benefited?
Answer:
In symbiotic nutrition both associates are benefited.

Question 14.
Why do some plants capture insects for nutrition?
Answer:
Some plants capture insects to fulfil the nutritional needs of nitrogen.

Question 15.
Which type of food is not digested in the stomach?
Answer:
Starch is not digested in the stomach.

Question 16.
Which type of carbohydrate is hydrolysed in stomach?
Answer:
Sucrose is hydrolysed in the stomach.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 17.
Which digestive juice is alkaline in nature?
Answer:
Bile is alkaline in nature.

Question 18.
Which acid makes the chyme acidic inside stomach?
Answer:
HCl makes the chyme acidic inside stomach.

Question 19.
Which digestive enzymes prefer lower pH to act properly?
Answer:
Pepsin and gastric lipase prefer lower pH to act properly.

Question 20.
By which process does food bolus reach stomach through oesophagus?
Answer:
Food bolus reaches the stomach through oesophagus by peristalsis.

Question 21.
From which gland is ptyalin secreted?
Answer:
Ptyalin is secreted from the salivary glands.

Question 22.
Which proteolytic enzyme is secreted from the pancreas?
Answer:
Trypsin is a proteolytic enzyme, secreted from the pancreas.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 23.
Which is the widest portion of the human GI tract?
Answer:
Large intestine or colon is the widest portion of the human GI tract.

Question 24.
What do bile salts do in digestion?
Answer:
Bile salts emulsify fat to help its enzymatic hydrolysis.

Question 25.
Which is the primary centre for protein digestion?
Answer:
Stomach is the primary centre for protein digestion.

Question 26.
Which, other than digestive enzymes, are secreted from pancreas?
Answer:
Other than digestive enzymes, hormones like insulin and glucagon are secreted from the pancreas.

Question 27.
From which cells HCl is secreted in stomach?
Answer:
HCl is secreted from oxyntic cells of inner lining of the stomach.

Question 28.
Which cells secrete digestive enzymes in small intestine?
Answer:
Digestive enzymes are secreted from Brunner’s gland cells inside the small intestine.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 29.
Which cells in stomach secrete digestive enzymes?
Answer:
The peptic cells or chief cells in the stomach, secrete digestive enzymes.

Question 30.
Which cells in intestine secrete mucus?
Answer:
Goblet cells in intestinal lining secrete mucus.

Question 31.
Name an enzyme, which prefers neutral or slightly alkaline pH for better action.
Answer:
Trypsin prefers neutral or slightly alkaline pH for better action.

Question 32.
Which enzyme hydrolyses protein into peptone?
Answer:
Pepsin hydrolyses protein into peptone.

Question 33.
Which enzyme hydrolyses fats into fatty acids and glycerol?
Answer:
Lipases hydrolyse fat into fatty acids and glycerol.

Question 34.
Which intestinal enzyme hydrolyses lower peptides into amino acids?
Answer:
Erepsin hydrolyses lower peptides into amino acids.

Question 35.
On which substrate does ptyalin act?
Answer:
Ptyalin acts upon boiled starch.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 36.
Which is the site for absorption of digested food?
Answer:
Villi inside the small intestine act as the site of absorption of digested food.

Question 37.
End products of which type of food are absorbed in blood capillaries of villi?
Answer:
End products of protein and carbohydrate digestion are absorbed in blood capillaries of villi.

Question 38.
End products of which type of food are absorbed in lacteals or fine lymph ducts of villi?
Answer:
End products of fats are absorbed in lacteals or fire lymph ducts of villi.

Question 39.
Which portion of human GI tract is responsible for absorption of excess water from residue of digestion?
Answer:
Colon is responsible for the absorption of excess water from the residue of digestion.

Question 40.
Which type of food does one need the most to fulfill the daily requirement of energy?
Answer:
Carbohydrate is needed the most to fulfill the daily requirement of energy.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 41.
Which nutritional insufficiency is the cause of hypothyroidism?
Answer:
Nutritional insufficiency of iodine is the cause of hypothyroidism.

Question 42.
Insufficiency of which hormone causes diabetes mellitus?
Answer:
Insufficiency of insulin from the beta-cells of the Islets of Langerhans of pancreas causes diabetes mellitus.

Question 43.
Which disease is caused due to impaired carbohydrate metabolism?
Answer:
Diabetes mellitus is caused by impaired carbohydrate metabolism.

Question 44.
Which disease is caused due to abnormal intake of high calorie diet?
Answer:
Obesity is caused due to abnormal intake of high calorie diet.

Question 45.
Which disease results into thickening of walls of arteries due to deposition of fat?
Answer:
In atherosclerosis, walls of arteries become thick and rigid due to deposition of fat.

Question 46.
Which disease results into transformation of liver cells into fibrous tissue?
Answer:
In liver cirrhosis, cells of liver are transformed into fibrous tissue.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 47.
Name an organism which performs both intracellular and extracellular digestion.
Answer:
Hydra performs both intracellular and extracellular digestion.

Question 48.
What is the function of lipids in blood?
Answer:
Lipids help to dissolve and transport vitamin A, D, E and K in blood.

Question 49.
What is bile comprised of?
Answer:
Bile is comprised of water, various inorganic salts, bile salts, bile pigments, fatty acids, cholesterol etc.

Question 50.
Name the bile salts.
Answer:
Sodium taurocholate and sodium glycocholate are the bile salts.

Question 51.
Name the two bile pigments.
Answer:
The two bile pigments are bilirubin and biliverdin.

Question 52.
Name the hormone secreted by the stomach.
Answer:
The hormone secreted by stomach is gastrin.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 53.
Name two lipolyitc enzymes present in human body.
Answer:
Two lipolytic enzymes present in human body are pancreatic lipase and gastric lipase.

Question 54.
Give two examples of pro-enzymes.
Answer:
Pepsinogen and trypsinogen are two examples of pro-enzymes.

Question 55.
Define apoenzyme.
Answer:
The protein part of a holoenzyme is known as apoenzyme.

Question 56.
What is a coenzyme?
Answer:
The organic non-protien part, which combines with the apoenzyme, thus forming a holoenzyme, is called coenzyme.

Question 57.
Name two coenzymes.
Answer:
NADP and NAD are two coenzymes.

Question 58.
Which process results in vomiting?
Answer:
Reverse peristalsis results in vomiting.

Short Questions and Answers : (2 marks for each question)

Question 1.
What is nutrition?
Answer:
Nutrition is a combination of processes, by which living organisms obtain the substances necessary for growth, developing resistance against diseases and acquiring potential energy for life by intake of food, digestion, absorption, assimilation and egestion (in animals) or by synthesis and assimilation (in plants).

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 2.
What is food?
Answer:
The edible matters, which a living organism consumes for growth, replenishing physical loss, developing resistance against diseases and acquiring energy for performing all life activities, are called food.

Question 3.
What is meant by autotrophic nutrition?
Answer:
The nutrition in which green plants and other phototrophic or chemoautotrophic organisms synthesize their own organic food from inorganic matters within their body cells is called autotrophic nutrition.

Question 4.
What is meant by heterotrophic nutrition?
Answer:
The nutrition in which organisms take in complex organic or inorganic matters as food, digest it before absorption and assimilation or absorb organic matters from dead and decaying plant and animal products is called heterotrophic nutrition. Example-All animals and nonphotosynthetic plants perform heterotrophic nutrition.

Question 5.
What is meant by holophytic nutrition?
Answer:
The physiological process in which autotrophic organisms perform nutrition by synthesising their own food and assimilating it within the body is called holophytic nutrition. Example-All green plants and photosynthetic organisms perform this type of nutrition.

Question 6.
What is meant by holozoic nutrition?
Answer:
The physiological process, which involves intake of complex organic or inorganic matter as food, followed by their digestion, absorption of endproducts of digestion, assimilation of essential nutrients within the protoplasm and finally egestion of undigested matters, is called holozoic nutrition. Example-All animals perform holozoic nutrition.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 7.
What is meant by saprophytic nutrition?
Answer:
The nutrition in which organisms absorb organic matter from dead and decaying plant and animal products is called saprophytic nutrition. ExampleDifferent fungi like Agaricus, Mucor, Penicillium, Saccharomyces etc. perform saprophytic nutrition.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 1
WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 2

Question 8.
What is meant by parasitic nutrition?
Answer:
The nutrition in which an organism (parasite) collects food from the body of another organism (host) for its growth and nourishment is known as the parasitic nutrition. In this process the parasite is benefited at the expense of the host. ExampleAmong plants, Cuscuta, Rafflesia, Puccinia perform parasitic nutrition. In animals, louse, tapeworm, roundworm show this type of nutrition.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 3

Question 9.
What is meant by symbiotic nutrition?
Answer:
The nutritional process where two different organisms depend upon each other to get nutrition and in this process both are benefited, is called symbiotic nutrition. Example-Rhizobium forms symbiotic relationship with roots of legumes.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 10.
What is meant by insectivorous nutrition?
Answer:
Certain plants capture insects with their specialised organs, dissolve it enzymatically and then absorb the nitrogen-rich sap to fulfil the need for extra nitrogen. This type of nutrition is called insectivorous nutrition. Example-Venusflytrap, sundew, pitcher plant etc.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 4

Question 11.
How many types of parasitic nutrition are found among parasitic animals? Give example of each.
Answer:
Two types of parasitic nutrition are seen among parasitic animals-
1. Ectoparasitic nutrition: In this nutrition, parasites collect food from outside the body of the host. Example-Louse performs this type of nutrition.
2. Endoparasitic nutrition: In this process, parasites collect nutrients from inside the body of the host. Example-Tapeworm, germs of malaria perform this type of nutrition.

Question 12.
What is meant by coprophagy?
Answer:
The faeces of animals contain a number of nutrients. Certain animals get these nutrients by consuming its own faeces or of other animals. This type of nutrition is called coprophagy. Example-Guinea pigs, rabbits consume their own faeces whereas pigs and dung beetle consume faeces of others to perform this type of nutrition.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 13.
What is sanguinivory?
Answer:
Certain animals perform nutrition by sucking blood from warm-blooded animals, this type of nutrition is called sanguinivory. ExampleMosquitoes, leeches, bedbugs, vampire bats perform this type of nutrition.

Question 14.
Mention the function of human tongue?
Answer:
Human tongue has many taste buds on it to taste different food. The taste buds at the tip are for tasting sweet food. The lateral buds are for tasting salty and sour food. The buds at the posterior region of tongue are for tasting bitter food. Besides tasting food, tongue helps in movement of food inside mouth to mix it with saliva. Tongue also helps in swallowing the bolus. It also takes part in articulation of speech.

Question 15.
What is meant by diphyodont teeth?
Answer:
In mammals teething occurs twice in the life time. The first set of teething occur after the age of six months. These are called milk teeth, which are 20 in number. These teeth fall at the age of six years which are replaced by 32 permanent teeth. This type of teeth of mammals are called diphyodont teeth.

Question 16.
What is meant by heterodont teeth?
Answer:
‘Hetero’ means different and ‘dont’ means teeth. In mammals, teeth are of different sizes and shapes according to their respective functions. Sharp and flat incisors are for cutting food. Pointed canines are used to tear, premolars and molars are used for rough and fine grinding. This type of teeth are called heterodont teeth.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 17.
What is meant by thecodont teeth?
Answer:
In mammals and in crocodiles the roots of teeth remain tightly embedded in the socket of jaws. This type of socketted teeth are called thecodont teeth.

Question 18.
Mention the dental formula of an adult person and a three year old baby.
Answer:
Dental formula of an adult individual-

I \(\frac{2}{2}\), C \(\frac{1}{1}\), PM\(\frac{2}{2}\), M \(\frac{3}{3}\)

Dental formula of a three year old child-

I \(\frac{2}{2}\), C \(\frac{1}{1}\), M\(\frac{2}{2}\)

Question 19.
What is pharynx? Mention its function.
Answer:
Pharynx: The posterior portion of the buccal cavity from where larynx and oesophagus start, is called pharynx.
Function: Pharynx helps in the flow of bolus into oesophagus and the passage of inspired and expired air through larynx.

Question 20.
What is oesophagus? What does it do?
Answer:
Oesophagus: Oesophagus is a 10-12 cm long tube, which comes down vertically from the base of pharynx to the stomach along the mid chest line.
Function: Oesophagus carries food bolus to stomach from the mouth.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 21.
Briefly mention the structure of stomach.
Answer:
Human stomach is a ‘J’ shaped highly extensible muscular sac. The upper portion of it, approaching the heart, is called the cardiac end. The body of stomach is known as fundus. The posterior end, approaching duodenum is called the pyloric end. Inner wall of stomach has many longitudinal ridges, called rugae.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 5

Question 22.
Write a brief description of human smail intestine.
Answer:
Small intestine of an adult human is a 6 metre long tube, which remains inside abdominal cavity in a densely coiled manner. It has three portions, the first one starts from the pyloric end of stomach, called duodenum. The next highly convoluted portion is known as jejunum. The last portion is called the ileum.

Small intestine is the site of final digestion and absorption of the digested food matters.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 6

Question 23.
Write a brief description of human colon.
Answer:
Colon or large intestine is the wider tube situated at the posterior portion of the human GI tract. It has four portions ascending colon, transverse colon, descending colon and sigmoid colon. The ascending arm emerges from the base of the caecum and the sigmoid colon ends at rectum. Colon is the site of water absorption and the formation of faeces from the undigested food.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 7

Question 24.
How many types of salivary glands are found in human body? Mention their location.
Answer:
There are three pairs of salivary glands in human mouth-

  1. Parotid gland-Located at the base of the ears.
  2. Sub-maxillary or submandibular gland-Located on two sides of lower jaw.
  3. Sub-lingual gland-Located below the tongue under the floor of mouth.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 8

Question 25.
Give a brief structural account of human liver.
Answer:
Liver is the largest gland of the human body. It is a dark reddish brown coloured triangular gland with two distinct lobes. Liver is lodged at the right side of the abdominal cavity just below the diaphragm. A club-shaped, thin-walled gall bladder is present on the lower side of the right hepatic lobe.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 9

Question 26.
Mention the functions of human liver.
Answer:
The functions of human liver are as follows

  1. Alkaline bile, secreted from liver, neutralizes acidic chyme from stomach.
  2. Bile salts emulsify fat to facilitate its digestion.
  3. Bile helps in the absorption of fat.
  4. Kupffer cells of liver kill germs by phagocytosis.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 27.
What is common bile duct?
Answer:
Hepatic ducts from right and left lobes of liver join to form a common hepatic duct. The cystic duct from the gall bladder comes to unite with the common hepatic duct to form a wider descending bile duct, called common bile duct.

Question 28.
Mention the functions of pancreas.
Answer:
The functions of pancreas are as follows :
1. Pancreas secretes both enzymes and hormones. Pancreatic juice contain amylolytic, lipolytic and proteolytic enzymes, which help in the hydrolysis of carbohydrate, fat and proteins respectively.
2. From α and β cells of islets of Langerhans two important hormones are secreted, which are glucagon and insulin respectively. These two hormones jointly regulate the sugar level of blood.

Question 29.
Mention the role of HCl in stomach.
Answer:
Role of HCl in stomach are as follows :

  1. HCl, secreted from oxyntic cells of the stomach wall, activates pepsinogen to active pepsin which helps in protein digestion.
  2. HCl helps in the hydrolysis of sucrose inside the stomach.
  3. HCl kills many germs, which enter into the stomach with the food.

Question 30.
Why should one chew food for some time before swallowing?
Answer:
One should chew food for some time before swallowing, because-

  1. Chewing helps in the grinding of food materials. Enzymes can act better or finely ground food particles.
  2. In the course of chewing, profuse salivary secretion occurs, which makes the bolus softer to ease swallowing.
  3. Chewing causes excess salivation, which helps in killing different bacteria by the action of lysozyme present in it.

Question 31.
Nams three proteolytic enzymes, their sources, substrates and the end products of hydrolysis.
Answer:
The following table shows sources, substrates and end products of three proteolytic enzymes.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 23

Question 32.
Name three amylolytic enzymes, their sources, substrates and the end products of hydrolysis.
Answer:
The following table shows sources, substrates and end products of three amylolytic enzymes.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 24

Question 33.
Mention the functions of stomach.
Answer:
The functions of stomach are as follows-

  1. Stomach holds the food for some time.
  2. HCl secreted from the stomach acidifies the food to kill germs, which enter along with it.
  3. HCl activates inactive proenzymes to active enzymes.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 34.
What is peristalsis?
Answer:
A wave of contraction and relaxation movement proceeds all along the alimentary tract from oesophagus to rectum. This typical movement is called peristalsis.
Peristalsis pushes the contents of the GI tract downwards.

Question 35.
What is meant by absorption? Where does it occur?
Answer:
Absorption: The process by which end products of digestion are taken into blood and lymph from intestine is called absorption.
Site: Though absorption mainly occurs in the ileum of small intestine, certain matters like some drugs, alcohol, salts etc., are also absorbed in the stomach and large intestine.

Question 36.
What are villi? What do they do?
Answer:
Villi: Villi are numerous tiny cylindrical fingerlike projections emerging from the inner wall of the small intestine.
Function: The blood vessels inside the villi absorb amino acids, simple sugars and glycerols from the small intestine. The lymph ducts or lacteals absorb all other end products of fat digestion.

Question 37.
What is meant by assimilation? Mention its significance.
Answer:
Assimilation: Assimilation is the process by which all essential ingredients of food are integrated in the protoplasm of living cells.
Significance: By assimilation, cells get necessary raw materials from which they synthesize essential cellular macromolecules as well as get necessary fuel, in the form of glucose and fats, to generate metabolic energy.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 38.
What is meant by egestion? What is its importance?
Answer:
Egestion: Egestion is the disposal of undigested food matter from rectum in the form of faeces.
Importance: By egestion, the post-digestive waste matter are removed from the GI tract to make it clear for normal functioning.

Question 39.
What is meant by metabolism?
Answer:
A series of constructive and destructive biochemical reactions continue in the protoplasm of all living cells to run the life activities, which are collectively called metabolism. The constructive reactions of metabolism are called anabolism and the destructive ones are known as catabolism.

Question 40.
What is anabolism?
Answer:
Anabolism is a metabolic process, by which some new molecules are synthesized or integrated within the protoplasm to increase the dry weight of an organism. ExamplePhotosynthesis and nutrition.

Question 41.
Mention the significance of anabolism in a living organism.
Answer:
Significance of anabolism are as follows

  1. Building up of organs and tissues.
  2. Growth and differentiation of cells.
  3. Synthesis and storage of complex molecules within the protoplasm.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 42.
What is catabolism?
Answer:
Catabolism is a metabolic process by which certain materials from protoplasm are utilized or broken down and as a result, the dry weight of an organism decreases. Example-Respiration and excretion.

Question 43.
Mention the significance of catabolism.
Answer:
Significance of catabolism are as follows-

  1. Providing kinetic energy for life activities.
  2. Releasing chemical energy for the synthesis of adenosine triphosphate (ATP).
  3. Disposal of harmful waste materials, produced in the body from different physiological reactions.

Question 44.
What is meant by balanced diet?
Answer:
The diet consisting of different food items including carbohydrates, proteins, lipids, vitamins, minerals and water in perfect quantities and proportions, in order to meet the requirement of the body for normal growth, replenishing physical loss, developing resistance against diseases and collecting potential energy necessary to perform all life activities, is called a balanced diet.

Question 45.
What is meant by basal metabolic rate? Mention the normal BMR of a healthy adult male and female individual.
Answer:
Basal metabolic rate: Basal metabolic rate is defined as per hour energy output of an individual, who is at complete physical and mental rest in a comfortable environment, 12 to 18 hours after taking a light meal.
Normal BMR values: BMR of a healthy adult male is 40 kcal / hour / sq.metre body surface.
BMR of a healthy adult female is 37 kcal / hour / sq.metre body surface.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 46.
Mention the calorific demand of a healthy adult man and a woman, performing normal job.
Answer:
The following table shows the calorific demand of a healthy adult man and a woman, performing normal job.

Class Body weight Calorific demand
Healthy adult male 60 kg 2730 kcal
Healthy adult female 55 kg 2230 kcal

Question 47.
Mention the diet of an adult individual according to daily energy requirement.
Answer:
The following table shows the diet of an adult individual according to daily energy requirement.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 25

Question 48.
What is meant by metabolic disorder?
Answer:
Within all the living cells several metabolic reactions go on continuously day and night. If any of these reactions go out of order due to insufficiency of any reactant (nutrients or substrates), enzyme or any physical factor, the effect is seen as abnormal life activity in an organism. This abnormality is known as metabolic disorder. Example- Diabetes mellitus, obesity, arthritis are some common metabolic disorders.

Question 49.
What is meant by hyperthyroidism? Mention its symptoms.
Answer:
Hyperthyroidism:The disorder related to increased secretion of thyroxin hormone from thyroid gland, is known as hyperthyroidism.
Symptoms: Symptoms of hyperthyroidism are-

  • Irregular heart rate
  • Hypertension
  • Increased BMR
  • Exophthalmic goitre.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 10

Question 50.
What is diabetes mellitus? Mention its symptoms.
Answer:
Diabetes mellitus: The metabolic disorder in which blood sugar level is elevated above normal (140 mg/100 ml blood) after two hours of taking full meal, due to insulin deficiency, is called diabetes mellitus.

Symptoms: Symptoms of diabetes mellitus are-

  • Frequent urination
  • Fatigue
  • Excessive urge for sweet food
  • Weight loss
  • Delayed healing of wounds
  • Boils and sores.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 51.
What is meant by obesity? Mention the problems related to obesity.
Answer:
Obesity: The metabolic disorder, noticed as very high body mass index (above 30), caused mainly due to intake of high calorie food beyond normal requirement of the body, is known as obesity.
Problems: Problems of obesity-

  • Loss of normal agility
  • Fatigue
  • Breathlessness
  • Hypertension
  • Cardiac disorder.

Question 52.
What is meant by atherosclerosis?
Answer:
The metabolic disorder in which fatty materials and WBCs accumulate on the inner wall of arteries to make it rough, non-elastic and reduce the diameter of arterial lumen, is known as atherosclerosis.

Question 53.
What is meant by liver cirrhosis?
Answer:
The metabolic disorder in which normal hepatic cells are transformed into fibrous scar tissues hindering normal secretory activities of liver and finally inactivating the liver function as a whole, is known as liver cirrhosis.

Question 54.
What is meant by arthritis?
Answer:
Arthritis is a metabolic disorder that involves painful inflammation and impaired movement of bone joints due to deposition of metabolic wastes in it or degradation of bones and cartilages.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 55.
What is caecotrophy?
Answer:
Certain mammals like rabbits, guinea pigs, etc. eject the semi-digested food of the caecum in the form of faeces or pellets, and engulf it again for complete digestion. This type of nutritional process is called caecotrophy. It is also known as coprophagy.

Question 56.
What do you understand by protein sparing foods?
Answer:
Protein sparing foods are foods other than proteins from which the body derives energy, obtain raw materials to synthesise cellular components as well as replenish physical loss. Generally carbohydrates are known as protein sparing foods and this type of function of carbohydrates is known as protein sparing action of carbohydrates.

Question 57.
All foods are nutrients but all nutrients are not food-Explain.
Answer:
All substances required for the overall nutrition and metabolism of the body, either directly or indirectly, are known as nutrients. Among them only the energy yielding nutrients such as carbohydrates, proteins and fats are generally considered as food. The others such as vitamins, mineral salts and water are incapable of yielding energy but are essential for growth, developing resistance against diseases, replenishing physical loss and thus, are called protective nutrients. Therefore, we can say that all foods are nutrients but all nutrients are not food.

Question 58.
Why milk cannot be considered as a balanced diet?
Answer:
Milk is generally deficient in vitamin C and iron (Fe) and therefore, an adult individual cannot obtain his/her required nutrients from milk. Thus, milk is not considered as a balanced diet in adults.
State the location and function of gall bladder.
Location: Gall bladder is located on the right side of the abdomen just beneath the right lobe of the liver.
Function: Its function is to store, concentrate and release bile which is produced by the liver.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 60.
Distinguish between anabolism and catabolism.
Answer:

Features Anabolism Catabolism
1. Nature Constructive metabolism Destructive metabolism
2. Dry weight Increases Decreases
3. Nature of transformation Simple molecules are transformed into complex organic matter Complex organic matters are broken down to simpler form
4. Example Photosynthesis and nutrition Respiration and excretion

Long Questions and Answers : (5 marks for each question)

Question 1.
Mention the different types of plant nutrition with example.
Answer:
Different types of plant nutrition with examples
Plants perform nutrition in different ways, which are mentioned below.
1. Autotrophic nutrition: In this process, plants perform nutrition by synthesising their own food from simple inorganic matters by photosynthesis followed by assimilation of the simple sugars produced in this process.
Example-All green plants, certain blue-green algae cyanobacteria, protists like Euglena, Chrysamoeba and photosynthetic bacteria like Rhodopseudomonas, Rhodospirillum etc.

2. Heterotrophic nutrition: The plants which cannot carry out photosynthesis due to the lack of photosynthetic pigments and depend on other living or dead or decaying organic matter of food, are called heterotrophs. Their mode of nutrition is called heterotrophic nutrition. These are discussed below.
Parasitic nutrition: In this process, some plants grow on other plants (called hosts) and draw nutrition from them.
Example-Plants like Cuscuta, Rafflesia, etc. show parasitic nutrition.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 11

Saprophytic nutrition: In this process, some plants draw nutrition from dead organisms and decaying organic matters.
Example-All types of fungi, like Agaricus, Mucor, Penicillium etc. perform saprophytic nutrition.

Symbiotic nutrition: In some cases, two different plants live in close association and are mutually benefited by that association. This mode of nutrition is called symbiotic nutrition. Example-Lichen is a symbiotic association of algae and fungi. Here, the fungal part provides the settling platform and water to the algal part. In return, the algae synthesise and supply food.

Insectivory: Certain plants draw nitrogenous nutrients from small insects. These plants have special organs, typically modified for trapping insects. This mode of nutrition is called insectivory.
Example-Pitcher plant, sundew, bladderwort are some plants which show insectivory.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 2.
Mention the different types of animal nutrition with example.
Answer:
Different types of animal nutrition
Animals cannot synthesise their own food like plants. For nutrition, they depend on food from plants or other animals. Animals perform three types of heterotrophic nutrition-holozoic, symbiotic and parasitic. These are discussed below.
1. Holozoic nutrition: This is a type of heterotrophic nutrition in animals, which is characterised by the intake and internal processing of the whole food. This is of the following types.
Herbivory: The mode of nutrition of animals, feeding on plants or plant parts is called herbivory.
Example-Cow, goat, monkey etc.
Carnivory: The mode of nutrition of animals feeding on the flesh of other animals is called carnivory.
Example-Tiger, lion, etc.
Coprophagy: Faeces of many animals contain nutritionally important substances. Some animals draw nutrients by consuming their own faeces, or of other animals. This type of nutrition is called coprophagy.
Example-Rabbits, guinea pigs, dung beetles etc. show coprophagy.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 12

Omnivory: The mode of nutrition of animals feeding on all types of food, of both plant or animal origin, is called omnivory.
Example-Man, dog, crows.

Carrion feeding: A few animals exclusively feed on flesh of dead animals for their nutrition. This is known as carrion feeding nutrition. Such animals are called scavengers.
Example-Vultures, hyenas etc.

2. Symbiotic nutrition: Sometimes, two animals develop a close association between them, from which both are nutritionally benefited. This type of nutrition is called symbiotic nutrition. Example-Escherichia coli (a bacterium) gets shelter and food in human intestine. In return, they synthesise vitamin.

3. Parasitic nutrition: Some animals draw nutrients from other living organisms (hosts);:thereby benefiting itself and harming the other. This mode of nutrition is called parasitic nutrition. Example-Plasmodium, Entamoeba, tapeworm, round worm etc. live inside the body of the host and are called endoparasites. Lice, ticks etc. live on the body surface of the host and are called ectoparasites. Some animals draw nutrients from blood of other animals. This mode of parasitic nutrition is called sanguinivory. Leeches, vampire bats etc. show this type of nutrition.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 3.
Briefly discuss the different phases of holozoic nutrition.
Answer:
Phases of holozoic nutrition
Holozoic nutrition involves five different phases, which are mentioned below.
1. Ingestion: In this step, food materials are taken into the mouth, chewed by teeth and are pushed into the food pipe or cesophagus. Besides teeth, tongue also helps in this process. Salivary secretion makes the food bolus softer to facilitate this process.

2. Digestion: This step involves mouth, stomach, liver, pancreas and small intestine. Several enzymes are secreted inside these organs from the glandular cells. In the presence of water, these enzymes act upon respective food materials and help in the breakdown of the matters into simple and absorbable forms. This step is known as hydrolysis or digestion of food.

3. Absorption: Mainly small intestine is involved in this process. Stomach and large intestine also play some role in it. End products of digestion are taken into the blood capillaries, where they are absorbed.

4. Assimiation: All tissues of the body are involved in this process. In this penultimate phase of holozoic nutrition. various nutritionally important compounds and ions, absorbed in the blood frum GI tract, enter into cells and become a part of the protoplasm.

5 Egestion: this process involves the rectum and anus of large intestine. In this last phase, undigested food matters are temporarily stured and then discharged as faeces.

Question 4.
Briefly describe the structure of human alimentary canal.
Answer:
Structure of human alimentary canal
The long tube or passage exiending from mouth to anus through which food passes during digestion is calied the alimentary canal. It is composed of the following parts-
1. Mouth: It is the opening of the alimentary canal, guarded by a pair of lips. The inner chamber is known as the buccal cavity, which consists of a muscular tongue at the base. The cavity also consists of an upper and a lower jaw, fitted with a maximum of 32 teeth (16 on each jaw).

2. Pharynx: It is slightly swollen, muscular chamber behind the buccal cavity.

3. Oesophagus: It is a straight, vertical, muscular tube, that carries food from the pharynx to the stomach.

4. Stomach: It is J-shaped muscular sac, present on the left side of the upper abdominal cavity. It consists of four regions-the cardiac stomach (upper portion, close to the heart), fundic stomach (wide middle portion), the body (portion between fundic stomach and pyloric stomach) and pyloric stomach (lower portion, attached to duodenum).

5. Small intestine: It is a very long, narrow and highly convoluted tube, that extends from the stomach to the large intestine and occupies maximum portion of the abdominal cavity. It has three portions-duodenum (emerging from stomach), jejunum (the middle region) and ileum (meets the large intestine).

6. Large intestine: This tube is less coiled and broader than small intestine. It consists of three parts-caecum (the dilated portion, where small intestine meets), colon (the tubular part consisting of four regions–ascending colon, transverse colon, descending colon and sigmoid colon), rectum (a wide tube, next to the sigmoid colon, that proceeds downward and opens through the anus).

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 5.
raw a labelled diagram of the human alimentary system.
Answer:
A labelled diagram of the human alimentary system

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 13

Question 6.
Briefly describe the different digestive glands of human alimentary system.
Answer:
Different digestive glands of human alimentary system
Human alimentary system consists of different types of digestive glands. These are discussed below.
1. Salivary glands: Three pairs of salivary glands are present in the buccal cavity.

  • Parotid glands: Situated at the base of two ears.
  • Submaxillary or submandibular glands: Situated on the two sides below the lower jaw.
  • Sublingual glands: Situated on either sides of the base of the tongue.

2. Gastric glands: Numerous, unicellular gastric glands present in the inner wall of the stomach.
3 Liver: It is the largest gland of the human body, placed below the diaphragm at upper right portion of the abdominal cavity. It has two distinct lobes-left lobe and right lobe. A balloonshaped gall bladder is present on the right lobe.
4. Pancreas: Leaf-shaped organ, transversely placed below the stomach within the duodenal arch.
5. Intestinal glands: Numerous unicellular glands are arranged in the inner wall of the intestine.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 7.
Mention the names, sources and roles of the different amylolytic enzymes in digestion.
Answer:
Different amylolytic enzymes in digestion
The names, sources and roles of different amylolytic enzymes that take part in digestion are given below.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 14

Question 8.
Mention the names, sources and roles of different proteolytic and lipolytic enzymes in digestion. 3 + 2
Answer:
Different proteolytic enzymes in digestion
The names, sources and roles of different proteolytic enzymes are given below.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 15

Different lipolytic enzymes in digestion
The names, sources and roles of different lipolytic enzymes are given below.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 16

Question 9.
How does absorption of digested food matters occur in the human GI tract? Briefly explain the method of assimilation of nutrients in the human body. 3 + 2
Answer:
Method of absorption of food
Absorption mainly occurs in the small intestine. The inner wall of the intestine develops many small finger-like projections called villi (singular-villus). Each villus has a central lymph duct called lacteal, and a few blood capillaries. Monosaccharides, amino acids and glycerol are absorbed in the blood capillares. Fatty acids are taken into the lacteals. Besides small intestine, a few materials are absorbed through the epithelial lining of the stomach and large intestine. These include water, alcohol, few salts and drugs.

Method of assimilation of food From the intestine, blood carries glucose, fructose, amino acids and a few fatty acid molecules to liver, through hepatic portal vessels. After supplying nutrients in the liver, this blood moves to systemic circulation. Lymph ducts carry simple fat molecules and finally transfer them to systemic circulation. As a result, all nutrients reach every tissue and cell through blood. Finally, these essential molecules are incorporated in the protoplasm of the cells.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 10.
Briefly explain the fate of the nutrients in a living cell. Mention the features of a balanced diet. 3 + 2
Answer:
Fate of nutrients in a living cell
The absorbed nutrients get assimilated within the cells and carry out different functions.
Monosaccharides participate in the cellular respiration as respiratory substrates. These are oxidised to generate energy, which is necessary for different life activities. Proteins help in building body cells and lipids are kept as stored matters. Vitamins act as coenzymes and minerals act as cofactors of various enzymes, or as fundamental components of some cellular molecules. Almost all end products of digestion undergo necessary changes within the cells by the process of metabolism.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 17

Features of a balanced diet Foods, that we take everyday, do not always make a balanced diet. Moreover, any single food material cannot be treated as a balanced diet. It should have certain features which are as follows-

  1. It should help to maintain the growth and perfect shape of the body.
  2. It should perfectly meet the calorific demand of a body.
  3. It should help to develop resistance against infection.

Question 11.
What do you understand by the term mechanical digestion? Mention the different types of mechanical digestion. 2+3
Answer:
Mechanical digestion
The process by which dry and semi-solid foods are converted into smaller fragments in the Gl tract and also the process by which the food is pushed forward along the G1 tract, is called mechanical digestion.

Different types of mechanical digestion
Generally mechanical digestion is of three types-
1. Mastication or chewing: Food matters taken into the buccal cavity undergo mechanical processing. Different types of teeth help to cut, tear and masticate the food matters into small particles. Saliva moistens it to form a soft and smooth dough-like matter. This whole process is known as mastication or chewing of food.

2. Swallowing: The process by which the food passes from the mouth to the pharynx and then enters the oesophagus by shutting the epiglottis, is known as swallowing or deglutition.

3. Movements of the GI tract: Movements of the gastro-intestinal tract occur which help in the forward movement of food. Generally two types of movements are seen-peristalsis and segmentation movement.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 12.
State the differences between small and large intestines. Distinguish between stomach and small intestine. 3 + 2
Answer:
Differences between small and large intestines

Features Small intestine Large intestine
1. Location in the gastrointestinal tract After the stomach After the small intestine
2. Structural parts Duodenum, jejunum and ileum Caecum, colon and rectum
3. Length 6-7 metres 1-1.5 metres
4. Diameter of the tract Smaller in diameter Larger in diameter
5. Function Digestion and absorption Absorption of water and mineral salts of and formation and storage of faeces

Differences between stomach and small intestine

Features Stomach Small intestine
1. Location After the oesophagus After the stomach
2. Shape Bag-shaped Tube-shaped
3. Parts 4 parts-cardiac, fundus, body and pyloric 3 parts-duodenum, jejunum and ileum
4. Function Temporary storage of food and partial digestion Complete digestion and absorption

Question 13.
Describe the different phases of protein digestion with the help of a suitable schematic diagram.
Different phases of protein digestion
Digestion of protein occurs stepwise, mostly in the stomach and small intestine. Several proteolytic enzymes (enzymes that break down protein) influence the process of protein digestion. The different phases of protein digestion are as follows-
1. Digestion in the buccal cavity: Since no proteolytic enzyme is present in the buccal cavity, protein digestion does not occur here.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 18

2. Digestion in the stomach: This is the site where protein digestion starts. Upon entering the stomach, the food is converted into chyle after it gets mixed with the gastric juice secreted from the gastric glands of the stomach. Presence of HCl in the gastric juice, makes the chyle acidic and activates the proteolytic enzyme pepsin. Pepsin converts proteins into peptones. However, pepsin is unable to execute the complete digestion of proteins into peptones and therefore, incomplete digestion of proteins occur in the stomach.

3. Digestion in the small intestine: Upon entering the small intestine, the undigested proteins and peptones mix with the pancreatic and the enteric juices. Proteolytic enzymes, named trypsin and chymotrypsin present the pancreatic juice hydrolyse peptones and undigested proteins into small peptides. After that, these small peptides are broken down into amino acids by the action of another enzyme, called erepsin, which is present in the enteric juice. These amino acids are then absorbed into the blood with the help of villi present in the small intestine.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 14.
Explain the different steps of carbohydrate digestion with the help of a suitable schematic diagram.
Answer:
Different steps of carbohydrate digestion
Carbohydrate digestion occurs mainly in the buccal cavity and in the small intestine.
Digestion in the buccal cavity: Carbohydrates’ specially boiled starch’ present in the food, mix with ptyalin present in the salivary juice and is converted to maltose and isomaltose. Maltase’ present in saliva’ converts maltose into 2 molecules of glucose. The quantity of maltase in the saliva is very low and therefore, small amounts of glucose is formed in the buccal cavity by the action of the salivary enzymes.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 19

2. Digestion in the stomach: Digestion of carbohydrates does not occur in the stomach due to absence of amylolytic or carbohydrate digesting enzymes. Only a small amount of sucrose is hydrolysed into glucose and fructose with the help of HCl.

3. Digestion in the smail intestine: In the small intestine, both boiled and unboiled starch get converted into maltose by the action of pancreatic amylase. Maltase present in enteric juice then breaks down maltose into 2 molecules of glucose. Majority of the ingested starch is broken down by pancreatic amylase. But if any portion of the starch is still left unbroken, then intestinal amylase will act on it to break it down into simpler components. Moreover, intestinal lactase and sucrase hydrolyse lactose into glucose and galactose and sucrose into glucose and fructose respectively. In this way, complex carbohydrates are broken down into simple monosaccharide units which are then absorbed in the body.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 15.
What do you mean by fat digestion? Briefly describe the different sieps involved in fat digestion. 1 + 4
Answer:
Fat digestion
The process by which fats or lipids are broken down into fatty acids and glycerol in the alimentary canal with help of the enzyme lipase and bile salts present in the digestive juice is called fat digestion.

Different steps of fat digestion
Fat digestion mainly occurs in the stomach and in the small intestine. The different steps of fat digestion are described below.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 20

1. Digestion in the buccal cavity: Fat digestion does not occur in the buccal cavity due to insufficient amount of fat digestive enzymes.
2. Digestion in the stomach: When the ingested food enters the stomach, it gets mixed with the gastric juice. Gastric lipase, present in the gastric juice, breaks down fats into fatty acids and glycerol.
3. Digestion in the small intestine: As the lipid molecules enter the duodenum of the small intestine, they get mixed with the bile, pancreatic and intestinal juices. The bile salts present in the bile juice emulsify the lipid molecules. Then pancreatic and intestinal lipases act on the emulsified fats and break them into fatty acids and glycerol. In this way, fat is broken down into fatty acids and glycerol which are then absorbed in the bloodstream.

Question 16.
What is basal metabolic rate? Mention the factors that regulate basal metabolic rate. 2 + 3
Answer:
Basal Metabolic Rate (BMR)

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 21

Basal metabolic rate is the amount of energy given out per hour and per square metre of body surface area of a person who is awake, but at complete mental and physical rest in comfortable environment and in a post-absorptive state, i.e. 12 to 18 hours after meal. It is the minimum amount of energy required to maintain vital physiological functions such as breathing, blood circulation etc. BMR of a healthy adult man is 40 kcal/hour/sq. metre body surface area and BMR of a healthy adult female is 37 kcal/hour/sq. metre body surface area. It is generally measured with the help of Benedict Roth apparatus.

Factors regulating basal metabolic rate
The factors which regulate the basal metabolic rate are discussed below.

  1. Body surface area: BMR is directly proportional to the body surface area.
  2. Age: Children have greater body surface area as compared to their body weight, therefore, in children BMR is more than in adults.
  3. Sex: Males have greater BMR than females.
  4. Nutritional status: Long term malnutrition causes decrease in BMR.
  5. Weather: People living in temperate regions have greater BMR than people living in warmer areas.
  6. Endocrine giands: Hormones secreted from thyroid, adrenal glands and anterior pituitary, increase BMR.
    Body temperature: BMR increases or decreases with increase or decrease of body temperature.

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 17.
State the significance of metaholism. What do you mean by metabolic disorders? State the reasons for metabolic problems in humans. 2+1+2
Answer:
Significance of metabolism
The significance of metabolism are as follows-
1. Maintenance of body homeostasis: Metabolism is essential for the normal functioning of all biochemical reactions taking place in the body.
2. Generation of energy: Metabolism provides energy, which is needed for the normal functioning of various body processes.

Metabolic disorders/problems
The condition in which normal body metabolism is altered, is called metabolic disorders or problems. Generally, metabolism decreases or sometimes halts in such conditons.

Reasons for metabolic disorders in humans
The reasons for metabolic disorders in humans are as follows-

1. Insufficient enzymes: A decrease in the functional enzymes is one of the main reasons of metabolic problems.
2. Insufficient hormones: Hormones generally regulate several metabolic processes. In absence of such hormones, these metabolic processes are altered leading to metabolic problems.
3. Genetic problems: Generally mutations of genes, involved in different metabolic pathways, lead to metabolic disorders.

Question 18.
Distinguish between autotrophic nutrition and heterotrophic nutrition.
Answer:
Differences between autotrophic nutrition and heterotrophic nutrition

Features Autotrophic nutrition Heterotrophic nutrition
1. Nutritional dependence Can synthesise own food hence, nutritionally independent Cannot synthesise their own food, hence nutritionally dependent upon other organisms
2. Chlorophyll Possess chlorophyll Do not possess chlorophyll
3. Nature of food Simple carbohydrate in solution Solid and complex organic and inorganic matters
4. Phases Two phases-synthesis and assimilation Five phases-ingestion, digestion, absorption, assimilation and egestion
5. Occurrence Occurs in green plants and some bacteria Occurs in all animals

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition

Question 19.
Compare among parasitic, saprophytic and symbiotic nutrition.
Answer:
Comparison among parasitic, saprophytic and symbiotic nutrition

WBBSE Class 9 Life Science Solutions Chapter 3.3 Nutrition 22

Question 20.
Distinguish between holophytic and holozoic nutrition.
Answer:
Differences between holophytic and holozoic nutrition

Features Autotrophic nutrition Heterotrophic nutrition
1. Nutritional dependence Can synthesise own food hence, nutritionally independent Cannot synthesise their own food, hence nutritionally dependent upon other organisms
2. Chlorophyll Possess chlorophyll Do not possess chlorophyll
3. Nature of food Simple carbohydrate in solution Solid and complex organic and inorganic matters
4. Phases Two phases-synthesis and assimilation Five phases-ingestion, digestion, absorption, assimilation and egestion
5. Occurrence Occurs in green plants and some bacteria Occurs in all animals